SkillAlign Skill Align
Australian Years 7–12 Online Practice | Year 12 Exam Packs
Cart, loading saved items

TASC General Mathematics Level 3 — Free Online Pack 0

Read TASC General Mathematics Level 3 online for free, including every question, worked solution, marking note and diagnostic action. No public PDF download or checkout is provided.

TASC Complete MTG315123 practice examination 2026 Edition - Pack 0 v2.0
Updated 26 Aug 2026

Practise more exam papers.Build confidence for unfamiliar questions.

An original exam simulation for this course

This pack is an original, independently prepared exam simulation. The governing document for this 2026 edition is identified in the course alignment above. Numbered packs in this course series are distinct resources for repeated full-paper exam practice. It is not an official TASC resource, and Skill Align is not affiliated with or endorsed by TASC.

TASC General Mathematics Level 3 is free to read in your browser. There is no public checkout or PDF download.

Exam-pack paper structure

This full-length showcase paper is available to read online.

TASC General Mathematics Level 3

28 questions

180 marks

Reading: 15 minutes preparation · Writing: 3 hours

Feedback about this exam pack

Found a question, answer, marking-guide, diagram or layout issue? The feedback form will open with this exam pack selected.

Send feedback about 2026 Edition - Pack 0

What Pack 0 covers

These areas are aggregated from the reviewed source for this exact pack. Question wording and answers remain private.

Covered in this pack

  • Section A; Bivariate data; Criterion 3; calculate predictions and evaluate domain and intercept limitations 5 marks · 1 question
  • Section A; Bivariate data; Criterion 3; identify confounding by comparing pooled and stratified percentages 7 marks · 1 question
  • Section A; Finance; Criterion 3; compare advertised rates with different compounding frequencies 4 marks · 1 question
  • Section A; Finance; Criterion 3; reconstruct and verify a loan recurrence from consecutive balances 8 marks · 1 question
  • Section A; Sequences; Criterion 3; compare linear and percentage-growth models 7 marks · 1 question
  • Section A; Sequences; Criterion 3; form and apply an arithmetic model 5 marks · 1 question
  • Section B; Bivariate data analysis; Criterion 5; construct and interpret conditional percentages and a comparative display 8 marks · 1 question
  • Section B; Bivariate data analysis; Criterion 5; construct scatter and residual plots, model bivariate data, and evaluate linear-model appropriateness 11 marks · 1 question
  • Section B; Time-series analysis; Criterion 5; calculate, plot and interpret centred moving averages 9 marks · 1 question
  • Section B; Time-series analysis; Criterion 5; use average-percentage seasonal indices, deseasonalisation and a least-squares time trend 8 marks · 1 question
  • Section C; Growth and decay in sequences; Criterion 6; compare arithmetic and geometric growth 10 marks · 1 question
  • Section C; Growth and decay in sequences; Criterion 6; infer the parameters and long-term behaviour of a first-order recurrence 8 marks · 1 question
  • Section C; Growth and decay in sequences; Criterion 6; recover a geometric model from separated terms and extend it 9 marks · 1 question
  • Section C; Growth and decay in sequences; Criterion 6; represent and apply an arithmetic sequence in tabular and graphical form 9 marks · 1 question
  • Section D; Finance; Criterion 7; compare standard and accelerated repayment schedules 9 marks · 1 question
  • Section D; Finance; Criterion 7; complete an effective-rate comparison table and apply the selected investment 8 marks · 1 question
  • Section D; Finance; Criterion 7; model an ordinary annuity and distinguish a perpetuity 9 marks · 1 question
  • Section D; Finance; Criterion 7; recover depreciation parameters from a table and compare later book values 10 marks · 1 question
  • Section E Part 1; Networks and decision mathematics; Criterion 8; apply the Hungarian algorithm to an assignment problem 6 marks · 1 question
  • Section E Part 1; Networks and decision mathematics; Criterion 8; construct and justify a minimum spanning tree 8 marks · 1 question
  • Section E Part 1; Networks and decision mathematics; Criterion 8; find and certify a maximum flow 8 marks · 1 question
  • Section E Part 1; Networks and decision mathematics; Criterion 8; find, compare and adapt shortest paths 7 marks · 1 question
  • Section E Part 1; Networks and decision mathematics; Criterion 8; use forward and backward scanning to analyse a project network 7 marks · 1 question
  • Section E Part 2; Trigonometry and Earth geometry; Criterion 8; calculate distance along a parallel of latitude 8 marks · 1 question
  • Section E Part 2; Trigonometry and Earth geometry; Criterion 8; create a labelled two-dimensional representation and apply non-right-triangle rules 7 marks · 1 question
  • Section E Part 2; Trigonometry and Earth geometry; Criterion 8; resolve a two-leg journey and calculate a true bearing 8 marks · 1 question
  • Section E Part 2; Trigonometry and Earth geometry; Criterion 8; solve a multi-stage journey using UTC offsets and the International Date Line 7 marks · 1 question
  • Section E Part 2; Trigonometry and Earth geometry; Criterion 8; solve a multi-step angle-of-depression problem 6 marks · 1 question

Read TASC General Mathematics Level 3 online

Skill Align

Skill Align TASC General Mathematics Level 3 - Free Online Pack 0

Current for 2026 | Course code MTG315123 | Five sections | 180 marks | 3 hours. Sections A-D are compulsory. In Section E, answer either Part 1 Networks and Decision Mathematics or Part 2 Applications of Trigonometry and Earth Geometry.

Paper
Full Practice Examination Showcase
Preparation time
15 minutes preparation
Working time
3 hours
Assessment
180 marks

A TASC-approved calculator and the current MTG315123 General Mathematics Information Sheet may be used throughout the examination. No other notes, internet access or external communication are permitted. Pack 0 is browser-only; no public PDF or reference-sheet download is supplied.

Section A - Mathematical and Statistical Models - Criterion 3 - 36 marks

Answer all six questions. This section allocates 12 marks each to bivariate data analysis, growth and decay in sequences, and finance. Suggested working time: 36 minutes.

Question 1

5 marks
A community energy planning program records 120 completed units in week 1 and then increases by 7 units each week.
(a) 2 marks
Write a recurrence relation for the weekly total t_n.
(b) 3 marks
Find the total in week 6.

Question 2

7 marks
Two forecasts begin at 900 participants. Model A adds 50 participants each period. Model G multiplies the previous total by 1.04 each period.
(a) 2 marks
Write a rule for each model, using period 1 as the initial period.
(b) 2 marks
Calculate both forecasts for period 4.
(c) 3 marks
Select the larger period-4 forecast and explain one limitation of extending either model for many periods.

Question 3

4 marks
Account M advertises 4.65% p.a. compounded monthly. Account Q advertises 4.73% p.a. compounded quarterly.
(a) 1 mark
State the periodic rate and number of periods per year for each account.
(b) 1 mark
Calculate both effective annual rates to two decimal places.
(c) 2 marks
Recommend the account with the greater effective return and state one non-rate factor that could change the decision.

Question 4

8 marks
A balance table for a monthly loan shows B_0 = AUD 21,500.00 and B_1 = AUD 20,916.75. Interest of 0.45% is added before an unknown equal repayment R is deducted.
(a) 2 marks
Calculate the first month's interest charge.
(b) 3 marks
Use the two balances to recover repayment R and write the recurrence relation.
(c) 3 marks
Use the reconstructed model to calculate B_2 to the nearest cent.

Question 5

5 marks
A study of community energy planning uses x = daily sunshine duration (hours) and y = daily solar energy output (MWh). Data were collected only for 2 <= x <= 8. The fitted line is y-hat = 8 + 2.4x.
(a) 1 mark
Calculate the fitted response at x = 5 and x = 12.
(b) 2 marks
Classify each prediction as interpolation or extrapolation and compare their reliability.
(c) 2 marks
Interpret the intercept mathematically and explain why a contextual interpretation may be inappropriate.

Question 6

7 marks
A program comparison for community energy planning is stratified by site type. At high-success sites, Program A has 81 successes from 90 cases and Program B has 9 from 10. At low-success sites, A has 1 success from 10 and B has 9 from 90.
(a) 3 marks
Calculate the success percentage for each program within each site type, then calculate the pooled percentage for each program.
(b) 4 marks
Explain why the pooled comparison is misleading and identify the confounding variable.

Section B - Bivariate Data Analysis - Criterion 5 - 36 marks

Answer all four questions on bivariate data and time-series analysis. Suggested working time: 36 minutes.

Question 7

11 marks
A study records explanatory variable x, daily sunshine duration (hours), and response variable y, solar energy output (MWh). The supplied ordered pairs are (1, 14), (2, 24), (3, 25), (4, 39), (5, 35), (6, 51), (7, 49), (8, 66).
(a) 2 marks
On labelled axes, construct a scatterplot of the eight ordered pairs and describe the direction, form and strength of the association.
(b) 3 marks
Use technology to find the least-squares regression line y-hat = a + bx and the correlation coefficient r. Give each value to three decimal places.
(c) 3 marks
Use technology to report r-squared directly, using the unrounded calculator value of r, and interpret it in context. Classify a prediction at x = 10 as interpolation or extrapolation and state one reliability concern.
(d) 3 marks
Calculate and interpret the residual for (4, 39). Then construct a residual plot from the calculator residual list and decide whether a linear model is appropriate.

Question 8

8 marks
A two-way frequency table records: urban, 46 Yes and 25 No; regional, 25 Yes and 36 No.
(a) 2 marks
Complete the row totals and overall total.
(b) 2 marks
Calculate the Yes and No row percentages for each location, to one decimal place.
(c) 2 marks
Construct a comparative percentage bar chart for the two locations.
(d) 2 marks
Describe the association and give one plausible non-causal explanation.

Question 9

9 marks
Seven successive monthly totals are 83, 89, 98, 94, 107, 111, 118.
(a) 3 marks
Calculate all five three-point moving averages, centred on months 2 to 6.
(b) 3 marks
On one set of labelled axes, plot the raw series and the centred moving-average series.
(c) 3 marks
Describe the underlying movement after smoothing and state one limitation of using only seven observations.

Question 10

8 marks
The quarterly totals for a community energy planning measure are Year 1: Q1 72.0, Q2 101.2, Q3 122.2, Q4 76.8; Year 2: Q1 78.4, Q2 110.0, Q3 132.6, Q4 83.2; Year 3: Q1 84.8, Q2 118.8, Q3 143.0, Q4 89.6. Let t = 1 for Year 1 Q1 and increase t by 1 each quarter.
(a) 2 marks
Use the average percentage method to calculate the four seasonal indices, to three decimal places. Check that their mean is approximately 1.
(b) 3 marks
Using the unrounded calculator seasonal index from part (a), deseasonalise the Year 3 Q1 total and interpret the result.
(c) 3 marks
Retain the unrounded seasonal-index values. Use technology to fit a least-squares line y-hat = a + bt to all 12 deseasonalised values. Forecast the next Q1 value at t = 13, reseasonalise it, and give both forecasts to one decimal place. State one assumption.

Section C - Growth and Decay in Sequences - Criterion 6 - 36 marks

Answer all four questions on arithmetic, geometric and first-order recurrence models. Suggested working time: 36 minutes.

Question 11

10 marks
Two models start at 210. Model A adds 13 each period. Model G grows by 4.2% each period.
(a) 3 marks
Write explicit rules for both models.
(b) 3 marks
Calculate both values at period 6.
(c) 4 marks
Identify which model is larger at period 6 and give one reason actual growth may follow neither model.

Question 12

9 marks
A geometric sequence table has t_2 = 345.600 and t_5 = 435.356. All terms are positive.
(a) 3 marks
Use t_5 / t_2 to find the common ratio, then recover t_1.
(b) 3 marks
Complete a table for n = 1 to 6 and plot the six terms as a discrete sequence graph.
(c) 3 marks
Write the explicit rule and calculate S_6, to one decimal place.

Question 13

9 marks
An arithmetic sequence has first term 36 and common difference 4.
(a) 3 marks
Write a recurrence relation and complete a table of n and t_n for n = 1 to 5.
(b) 3 marks
On labelled axes, plot the five table values as a discrete sequence graph.
(c) 3 marks
Write an explicit rule, then find t_12 and the sum of the first 12 terms.

Question 14

8 marks
A sequence is known to have the form u_(n+1) = au_n + c. Its first three values are u_0 = 82, u_1 = 70 and u_2 = 62.8.
(a) 2 marks
Form two equations and determine a and c.
(b) 3 marks
Use the inferred recurrence to calculate u_5, to two decimal places.
(c) 3 marks
Calculate the steady value and justify the long-term behaviour.

Section D - Finance - Criterion 7 - 36 marks

Answer all four questions on investments, loans, annuities, perpetuities and depreciation. Suggested working time: 36 minutes.

Question 15

9 marks
An account starts at A_0 = 0 and follows A_(n+1) = 1.0041A_n + 230, with each deposit made at the end of the month. A separate preserved-principal fund contains AUD 25,000.00 and earns 4.25% effective p.a.
(a) 2 marks
Calculate A_1 and A_2.
(b) 2 marks
Write A_n as a finite geometric sum.
(c) 2 marks
Calculate the balance after 12 deposits, to the nearest cent.
(d) 3 marks
Treat the separate fund as a perpetuity. Calculate the sustainable annual withdrawal and state one assumption.

Question 16

9 marks
A loan of AUD 32,000.00 uses monthly multiplier 1.0055. The standard payment is AUD 980.00. An accelerated plan adds AUD 180.00 to every payment for the first six months.
(a) 3 marks
Write a recurrence relation for each six-month plan.
(b) 3 marks
Use technology to calculate both balances after six payments and the difference between them, to the nearest cent.
(c) 3 marks
Compare the interest charged over the six months and explain why the balance difference exceeds the six extra payments alone.

Question 17

10 marks
An asset costs AUD 36,000.00. A partial year-end table shows: straight-line value after year 1, AUD 32,400.00; reducing-balance value after year 1, AUD 29,520.00.
(a) 2 marks
Use the straight-line row to recover the annual depreciation amount and write V_n.
(b) 2 marks
Use the reducing-balance row to recover the annual depreciation rate and write R_n.
(c) 3 marks
Calculate both book values after five years, to the nearest cent.
(d) 3 marks
State which method records more accumulated depreciation after five years and quantify the difference.

Question 18

8 marks
A AUD 9,000.00 investment is available for three years. Offer M pays 4.8% p.a. compounded monthly. Offer Q pays 4.9% p.a. compounded quarterly.
(a) 2 marks
Complete a comparison table showing each periodic rate and its number of compounding periods per year.
(b) 3 marks
Calculate each effective annual rate to three decimal places and select the greater return.
(c) 3 marks
Use the selected offer to calculate the value after three years, to the nearest cent, and state one assumption.

Section E - Part 1 - Networks and Decision Mathematics - Criterion 8 - 36 marks

Choose Part 1 OR Part 2. If you choose Part 1, answer all five network questions. Suggested working time for the selected part: 36 minutes.

Question 19

6 marks
For a community energy planning program, four coordinators A-D must each be assigned one distinct task 1-4. The cost matrix is A [9, 2, 7, 8]; B [6, 4, 3, 7]; C [5, 8, 1, 8]; D [7, 6, 9, 4].
(a) 2 marks
Perform the row-reduction step. State the four row minima and the row-reduced matrix.
(b) 2 marks
Complete the column-reduction step and identify four independent zeros.
(c) 2 marks
State the optimal assignment and calculate its total cost from the original matrix.

Question 20

7 marks
The weighted network shows route lengths between locations A-E.
Diagram Preview
Undirected network: A-B, length 1; A-C, length 5; B-C, length 2; B-D, length 7; C-D, length 3; C-E, length 10; D-E, length 4. 1 5 2 7 3 10 4ABCDE
(a) 3 marks
Find a shortest route from A to E and its total length.
(b) 4 marks
Edge C-D closes. Find the new shortest route from A to E and explain why the original route can no longer be used.

Question 21

8 marks
The weighted network connects five service sites. All edge weights are shown.
Diagram Preview
Undirected network: A-B, weight 3; B-C, weight 4; C-D, weight 5; D-E, weight 6; A-C, weight 11; B-D, weight 12; C-E, weight 13. 3 4 5 6 11 12 13ABCDE
(a) 4 marks
Use Prim's algorithm to list the edges in one minimum spanning tree.
(b) 4 marks
Find the total weight and explain why the three longer diagonal edges are excluded.

Question 22

7 marks
The activity-on-node diagram shows a community energy planning project. Durations are in days, and the arrows show the required task order.
Diagram Preview
Directed network: start to A (3); start to B (5); A (3) to C (4); A (3) to D (2); B (5) to E (5); D (2) to E (5); C (4) to F (3); E (5) to F (3); F (3) to finish. startA (3)B (5)C (4)D (2)E (5)F (3)finish
(a) 2 marks
Complete a forward scan and state the EST for activities C, D, E and F and the minimum project duration.
(b) 2 marks
Complete a backward scan and state the LST for activities A-F.
(c) 3 marks
Calculate the float of each activity and identify the critical path.

Question 23

8 marks
The directed community energy planning network shows capacities from source S to sink T.
Diagram Preview
Directed network: S to A, capacity 6; S to B, capacity 5; A to B, capacity 2; A to T, capacity 4; B to T, capacity 5. 6 5 2 4 5SABT
(a) 4 marks
Give a feasible flow of value 9 from S to T.
(b) 4 marks
Identify a cut that proves the flow is maximum.

Section E - Part 2 - Applications of Trigonometry and Earth Geometry - Criterion 8 - 36 marks

Choose Part 1 OR Part 2. If you choose Part 2, answer all five trigonometry and Earth-geometry questions. Do not answer both parts. Suggested working time for the selected part: 36 minutes.

Question 24

8 marks
A survey vessel travels 16 km on a true bearing of 030 degrees, then 21 km on a true bearing of 112 degrees.
(a) 2 marks
Calculate the total eastward and northward displacement components, to two decimal places.
(b) 3 marks
Calculate the straight-line distance from the starting point, to two decimal places.
(c) 3 marks
Find the true bearing of the vessel from its starting point, to the nearest degree, and explain the quadrant check.

Question 25

8 marks
Two locations lie on latitude 38 degrees south and differ by 6 degrees of longitude. Model Earth as a sphere of radius 6370 km.
(a) 2 marks
Find the radius of the parallel of latitude, to the nearest kilometre.
(b) 3 marks
Calculate the distance along the parallel, to the nearest kilometre.
(c) 3 marks
Estimate the travel time at a constant ground speed of 700 km / h, to the nearest minute, and state one limitation.

Question 26

7 marks
Two sides of a triangular site are 7.2 km and 9.3 km, with included angle 52 degrees.
(a) 2 marks
Draw a labelled two-dimensional sketch showing the two known sides, the included angle and the unknown side c.
(b) 2 marks
Use your sketch to find side c, to two decimal places.
(c) 3 marks
Find the area of the triangle, to two decimal places.

Question 27

7 marks
A journey leaves City A (UTC+10) on Wed 14 Oct at 19:20. The first flight lasts 5 h 20 min, followed by a 1 h 45 min stopover in City B (UTC+12). The second flight lasts 7 h 10 min to City C (UTC-8), crossing the International Date Line eastward. Use the stated offsets and ignore daylight saving.
(a) 2 marks
Convert the City A departure to UTC and find the local arrival date and time in City B.
(b) 2 marks
Find the City B local departure date and time after the stopover, and convert it to UTC.
(c) 3 marks
Find the local arrival date and time in City C and the total elapsed journey time. State one assumption.

Question 28

6 marks
From a horizontal viewing platform 32 m above sea level, the angle of depression to boat P is 24 degrees. Boat Q is on the same straight bearing and has angle of depression 32 degrees.
(a) 2 marks
Explain why each angle of depression equals the corresponding angle of elevation from the boat.
(b) 2 marks
Calculate the horizontal distance from the platform base to each boat, to one decimal place.
(c) 2 marks
Find the distance between the boats and state one assumption needed for the subtraction.

TASC courses, assessment and certification are administered by the Tasmanian Assessment, Standards and Certification office. Skill Align is an independent publisher and is not affiliated with, authorised by, sponsored by, approved by or endorsed by TASC or the Tasmanian Government. This is an original Skill Align practice examination, not an official TASC examination.

Copyright (c) 2026 Skill Align. Free for personal, non-commercial online viewing at https://skillalign.au. You may share the Skill Align page link. Except as permitted by law or with Skill Align's prior written permission, the pack itself must not be resold, copied, redistributed, republished, automatically extracted, or uploaded to a question bank.

Worked Solutions And Marking Guide

General marking principles

  • Award marks in 0.5-mark increments against the question-specific checkpoints and accept mathematically equivalent working.
  • For a 1-mark item, award 1 mark for a correct answer with or without working, and 0.5 mark for an incorrect answer that includes some correct relevant working.
  • For a 2-mark item, relevant working is required for full marks; a correct answer with no working receives no more than 1.5 marks.
  • For an item worth 3 or 4 marks, a correct answer with no relevant working receives no more than half the available marks; use 0.5-mark partial credit for demonstrated correct progress.
  • Apply consequential marking where later work correctly uses an earlier value without making the later task easier.
  • Assess only one Section E part and do not combine achievements from both alternatives.
  • Use these Skill Align diagnostics as revision guidance, not as official TASC criterion ratings.

Section A Question 1

(a) t_1 = 120, t_(n+1) = t_n + 7.

Identify the initial value and constant weekly change.

(b) 155 units.

Calculate 120 + 5 × 7 = 155.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Identify the initial value and constant weekly change.; Obtains or justifies: t_1 = 120, t_(n+1) = t_n + 7..
  • Part b: Establishes a valid setup consistent with: Calculate 120 + 5 × 7 = 155.; Carries the setup through the required calculation or representation for part b.; Obtains or justifies: 155 units..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Identify the initial value and constant weekly change.
  2. Obtains or justifies: t_1 = 120, t_(n+1) = t_n + 7.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Calculate 120 + 5 × 7 = 155.
  2. Carries the setup through the required calculation or representation for part b.
  3. Obtains or justifies: 155 units.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section A Question 2

(a) A_n = 900 + 50(n - 1); G_n = 900(1.04)^(n - 1).

Translate the constant and percentage changes into explicit sequence rules.

(b) A_4 = 1050; G_4 is approximately 1012.3776.

Substitute n = 4 into both models.

(c) The arithmetic model is larger at period 4. Neither constant numerical growth nor constant percentage growth is guaranteed indefinitely because capacity and conditions can change.

Compare the calculated values, identify the larger result, and evaluate the constant-growth assumption.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Translate the constant and percentage changes into explicit sequence rules.; Obtains or justifies: A_n = 900 + 50(n - 1); G_n = 900(1.04)^(n - 1)..
  • Part b: Establishes a valid setup consistent with: Substitute n = 4 into both models.; Obtains or justifies: A_4 = 1050; G_4 is approximately 1012.3776..
  • Part c: Establishes a valid setup consistent with: Compare the calculated values, identify the larger result, and evaluate the constant-growth assumption.; Carries the setup through the required calculation or representation for part c.; Obtains or justifies: The arithmetic model is larger at period 4. Neither constant numerical growth nor constant percentage growth is guaranteed indefinitely because capacity and conditions can change..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Translate the constant and percentage changes into explicit sequence rules.
  2. Obtains or justifies: A_n = 900 + 50(n - 1); G_n = 900(1.04)^(n - 1).

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Substitute n = 4 into both models.
  2. Obtains or justifies: A_4 = 1050; G_4 is approximately 1012.3776.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Compare the calculated values, identify the larger result, and evaluate the constant-growth assumption.
  2. Carries the setup through the required calculation or representation for part c.
  3. Obtains or justifies: The arithmetic model is larger at period 4. Neither constant numerical growth nor constant percentage growth is guaranteed indefinitely because capacity and conditions can change.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section A Question 3

(a) M: 0.388% per month and 12 periods. Q: 1.183% per quarter and 4 periods.

Divide each nominal annual rate by its compounding frequency.

(b) M: 4.75% effective p.a.; Q: 4.81% effective p.a.

Apply (1 + periodic rate)^(periods per year) - 1 to each account.

(c) Account Q has the greater effective annual rate. Fees, access restrictions, risk or a rate change could alter the practical choice.

Compare like-for-like effective rates and identify a relevant model limitation.

Mark allocation

  • Part a: Obtains or justifies: M: 0.388% per month and 12 periods. Q: 1.183% per quarter and 4 periods..
  • Part b: Obtains or justifies: M: 4.75% effective p.a.; Q: 4.81% effective p.a..
  • Part c: Establishes a valid setup consistent with: Compare like-for-like effective rates and identify a relevant model limitation.; Obtains or justifies: Account Q has the greater effective annual rate. Fees, access restrictions, risk or a rate change could alter the practical choice..

Detailed marking criteria

Part a (1 mark)

Award 1 mark for a correct answer with or without working. Award 0.5-mark partial credit for an incorrect answer that shows some correct relevant working; otherwise award 0 marks.

Indicative checkpoints (0.5-mark increments allowed):

  1. Obtains or justifies: M: 0.388% per month and 12 periods. Q: 1.183% per quarter and 4 periods.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (1 mark)

Award 1 mark for a correct answer with or without working. Award 0.5-mark partial credit for an incorrect answer that shows some correct relevant working; otherwise award 0 marks.

Indicative checkpoints (0.5-mark increments allowed):

  1. Obtains or justifies: M: 4.75% effective p.a.; Q: 4.81% effective p.a.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Compare like-for-like effective rates and identify a relevant model limitation.
  2. Obtains or justifies: Account Q has the greater effective annual rate. Fees, access restrictions, risk or a rate change could alter the practical choice.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section A Question 4

(a) Interest = AUD 96.75.

Multiply the opening balance by the monthly rate.

(b) R = AUD 680.00 and B_(n+1) = 1.0045B_n - 680.

Rearrange B_1 = (1 + i)B_0 - R, then retain the interest-before-payment order.

(c) B_2 = AUD 20,330.88.

Apply one further complete monthly cycle to B_1.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Multiply the opening balance by the monthly rate.; Obtains or justifies: Interest = AUD 96.75..
  • Part b: Establishes a valid setup consistent with: Rearrange B_1 = (1 + i)B_0 - R, then retain the interest-before-payment order.; Carries the setup through the required calculation or representation for part b.; Obtains or justifies: R = AUD 680.00 and B_(n+1) = 1.0045B_n - 680..
  • Part c: Establishes a valid setup consistent with: Apply one further complete monthly cycle to B_1.; Carries the setup through the required calculation or representation for part c.; Obtains or justifies: B_2 = AUD 20,330.88..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Multiply the opening balance by the monthly rate.
  2. Obtains or justifies: Interest = AUD 96.75.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Rearrange B_1 = (1 + i)B_0 - R, then retain the interest-before-payment order.
  2. Carries the setup through the required calculation or representation for part b.
  3. Obtains or justifies: R = AUD 680.00 and B_(n+1) = 1.0045B_n - 680.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Apply one further complete monthly cycle to B_1.
  2. Carries the setup through the required calculation or representation for part c.
  3. Obtains or justifies: B_2 = AUD 20,330.88.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section A Question 5

(a) At x = 5, y-hat = 20 MWh; at x = 12, y-hat = 36.8 MWh.

Substitute each explanatory value into the fitted line and retain the response unit.

(b) The x = 5 prediction is interpolation within the observed domain. The x = 12 prediction is extrapolation and is less reliable because the fitted relationship may not continue beyond x = 8.

Compare each input with the stated data domain.

(c) The intercept predicts 8 MWh at x = 0, but x = 0 lies outside the observed domain and may be impossible or irrelevant in this study.

State the model value at zero, then test zero against the data range and context.

Mark allocation

  • Part a: Obtains or justifies: At x = 5, y-hat = 20 MWh; at x = 12, y-hat = 36.8 MWh..
  • Part b: Establishes a valid setup consistent with: Compare each input with the stated data domain.; Obtains or justifies: The x = 5 prediction is interpolation within the observed domain. The x = 12 prediction is extrapolation and is less reliable because the fitted relationship may not continue beyond x = 8..
  • Part c: Establishes a valid setup consistent with: State the model value at zero, then test zero against the data range and context.; Obtains or justifies: The intercept predicts 8 MWh at x = 0, but x = 0 lies outside the observed domain and may be impossible or irrelevant in this study..

Detailed marking criteria

Part a (1 mark)

Award 1 mark for a correct answer with or without working. Award 0.5-mark partial credit for an incorrect answer that shows some correct relevant working; otherwise award 0 marks.

Indicative checkpoints (0.5-mark increments allowed):

  1. Obtains or justifies: At x = 5, y-hat = 20 MWh; at x = 12, y-hat = 36.8 MWh.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Compare each input with the stated data domain.
  2. Obtains or justifies: The x = 5 prediction is interpolation within the observed domain. The x = 12 prediction is extrapolation and is less reliable because the fitted relationship may not continue beyond x = 8.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: State the model value at zero, then test zero against the data range and context.
  2. Obtains or justifies: The intercept predicts 8 MWh at x = 0, but x = 0 lies outside the observed domain and may be impossible or irrelevant in this study.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section A Question 6

(a) High-success sites: A 90% and B 90%. Low-success sites: A 10% and B 10%. Pooled: A 82% and B 18%.

Use the site-specific denominators first, then pool the successes and cases by program.

(b) Within each site type the programs have equal success rates. The pooled difference arises because Program A has far more cases at high-success sites and Program B has far more at low-success sites. Site type is the confounding variable, so the pooled association should not be interpreted as a program effect.

Compare conditional and pooled results and link the reversal to unequal group composition.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Use the site-specific denominators first, then pool the successes and cases by program.; Carries the setup through the required calculation or representation for part a.; Obtains or justifies: High-success sites: A 90% and B 90%. Low-success sites: A 10% and B 10%. Pooled: A 82% and B 18%..
  • Part b: Establishes a valid setup consistent with: Compare conditional and pooled results and link the reversal to unequal group composition.; Carries the setup through the required calculation or representation for part b.; Addresses the requested accuracy, unit, comparison or interpretation in: Explain why the pooled comparison is misleading and identify the confounding variable.; Obtains or justifies: Within each site type the programs have equal success rates. The pooled difference arises because Program A has far more cases at high-success sites and Program B has far more at low-success sites. Site type is the confounding variable, so the pooled association should not be interpreted as a program effect..

Detailed marking criteria

Part a (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Use the site-specific denominators first, then pool the successes and cases by program.
  2. Carries the setup through the required calculation or representation for part a.
  3. Obtains or justifies: High-success sites: A 90% and B 90%. Low-success sites: A 10% and B 10%. Pooled: A 82% and B 18%.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (4 marks)

Award up to 4 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 2.0 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Compare conditional and pooled results and link the reversal to unequal group composition.
  2. Carries the setup through the required calculation or representation for part b.
  3. Addresses the requested accuracy, unit, comparison or interpretation in: Explain why the pooled comparison is misleading and identify the confounding variable.
  4. Obtains or justifies: Within each site type the programs have equal success rates. The pooled difference arises because Program A has far more cases at high-success sites and Program B has far more at low-success sites. Site type is the confounding variable, so the pooled association should not be interpreted as a program effect.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section B Question 7

(a) A correctly scaled and labelled scatterplot of (1, 14), (2, 24), (3, 25), (4, 39), (5, 35), (6, 51), (7, 49), (8, 66). The association is positive, approximately linear, and strong.

Plot every supplied pair at the correct coordinate and describe direction, form and strength.

(b) y-hat = 7.714 + 6.702x; r = 0.965.

Enter the paired data in corresponding lists, calculate linear regression, and report the coefficient order correctly.

(c) r-squared = 0.932. About 93.2% of the variation in solar energy output is explained by its fitted linear relationship with daily sunshine duration. A prediction at x = 10 is extrapolation beyond the observed range 1 to 8, so the fitted pattern may not continue and the result is less reliable.

Report the calculator's coefficient of determination, name both variables in the explained-variation statement, and compare the prediction input with the observed domain.

(d) The residual is 4.48 MWh, so the observed solar energy output is 4.48 MWh above the fitted value. Residual points: (1, -0.42), (2, 2.88), (3, -2.82), (4, 4.48), (5, -6.23), (6, 3.07), (7, -5.63), (8, 4.67). A linear model is reasonably appropriate because the residuals are scattered on both sides of zero without a systematic curved pattern.

Use observed minus fitted for the named residual, plot residual against the explanatory variable with a zero reference line, then use random scatter or systematic curvature to assess the linear model.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Plot every supplied pair at the correct coordinate and describe direction, form and strength.; Obtains or justifies: A correctly scaled and labelled scatterplot of (1, 14), (2, 24), (3, 25), (4, 39), (5, 35), (6, 51), (7, 49), (8, 66). The association is positive, approximately linear, and strong..
  • Part b: Establishes a valid setup consistent with: Enter the paired data in corresponding lists, calculate linear regression, and report the coefficient order correctly.; Carries the setup through the required calculation or representation for part b.; Obtains or justifies: y-hat = 7.714 + 6.702x; r = 0.965..
  • Part c: Establishes a valid setup consistent with: Report the calculator's coefficient of determination, name both variables in the explained-variation statement, and compare the prediction input with the observed domain.; Carries the setup through the required calculation or representation for part c.; Obtains or justifies: r-squared = 0.932. About 93.2% of the variation in solar energy output is explained by its fitted linear relationship with daily sunshine duration. A prediction at x = 10 is extrapolation beyond the observed range 1 to 8, so the fitted pattern may not continue and the result is less reliable..
  • Part d: Establishes a valid setup consistent with: Use observed minus fitted for the named residual, plot residual against the explanatory variable with a zero reference line, then use random scatter or systematic curvature to assess the linear model.; Carries the setup through the required calculation or representation for part d.; Obtains or justifies: The residual is 4.48 MWh, so the observed solar energy output is 4.48 MWh above the fitted value. Residual points: (1, -0.42), (2, 2.88), (3, -2.82), (4, 4.48), (5, -6.23), (6, 3.07), (7, -5.63), (8, 4.67). A linear model is reasonably appropriate because the residuals are scattered on both sides of zero without a systematic curved pattern..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Plot every supplied pair at the correct coordinate and describe direction, form and strength.
  2. Obtains or justifies: A correctly scaled and labelled scatterplot of (1, 14), (2, 24), (3, 25), (4, 39), (5, 35), (6, 51), (7, 49), (8, 66). The association is positive, approximately linear, and strong.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Enter the paired data in corresponding lists, calculate linear regression, and report the coefficient order correctly.
  2. Carries the setup through the required calculation or representation for part b.
  3. Obtains or justifies: y-hat = 7.714 + 6.702x; r = 0.965.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Report the calculator's coefficient of determination, name both variables in the explained-variation statement, and compare the prediction input with the observed domain.
  2. Carries the setup through the required calculation or representation for part c.
  3. Obtains or justifies: r-squared = 0.932. About 93.2% of the variation in solar energy output is explained by its fitted linear relationship with daily sunshine duration. A prediction at x = 10 is extrapolation beyond the observed range 1 to 8, so the fitted pattern may not continue and the result is less reliable.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part d (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Use observed minus fitted for the named residual, plot residual against the explanatory variable with a zero reference line, then use random scatter or systematic curvature to assess the linear model.
  2. Carries the setup through the required calculation or representation for part d.
  3. Obtains or justifies: The residual is 4.48 MWh, so the observed solar energy output is 4.48 MWh above the fitted value. Residual points: (1, -0.42), (2, 2.88), (3, -2.82), (4, 4.48), (5, -6.23), (6, 3.07), (7, -5.63), (8, 4.67). A linear model is reasonably appropriate because the residuals are scattered on both sides of zero without a systematic curved pattern.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section B Question 8

(a) Urban: 71; regional: 61; overall: 132.

Add within rows and then combine the row totals.

(b) Urban: Yes 64.8%, No 35.2%; regional: Yes 41.0%, No 59.0%.

Use each row total as the denominator and check that each row sums to 100%.

(c) Two correctly labelled 100% bars, partitioned at the calculated Yes and No percentages, with a legend or direct labels.

Use a common percentage scale so the conditional distributions can be compared.

(d) The higher urban Yes percentage indicates an association between location and response. A confounding factor such as service access, age profile or sampling method could explain part of the difference.

Compare the conditional distributions and name a plausible confounder.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Add within rows and then combine the row totals.; Obtains or justifies: Urban: 71; regional: 61; overall: 132..
  • Part b: Establishes a valid setup consistent with: Use each row total as the denominator and check that each row sums to 100%.; Obtains or justifies: Urban: Yes 64.8%, No 35.2%; regional: Yes 41.0%, No 59.0%..
  • Part c: Establishes a valid setup consistent with: Use a common percentage scale so the conditional distributions can be compared.; Obtains or justifies: Two correctly labelled 100% bars, partitioned at the calculated Yes and No percentages, with a legend or direct labels..
  • Part d: Establishes a valid setup consistent with: Compare the conditional distributions and name a plausible confounder.; Obtains or justifies: The higher urban Yes percentage indicates an association between location and response. A confounding factor such as service access, age profile or sampling method could explain part of the difference..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Add within rows and then combine the row totals.
  2. Obtains or justifies: Urban: 71; regional: 61; overall: 132.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Use each row total as the denominator and check that each row sums to 100%.
  2. Obtains or justifies: Urban: Yes 64.8%, No 35.2%; regional: Yes 41.0%, No 59.0%.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Use a common percentage scale so the conditional distributions can be compared.
  2. Obtains or justifies: Two correctly labelled 100% bars, partitioned at the calculated Yes and No percentages, with a legend or direct labels.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part d (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Compare the conditional distributions and name a plausible confounder.
  2. Obtains or justifies: The higher urban Yes percentage indicates an association between location and response. A confounding factor such as service access, age profile or sampling method could explain part of the difference.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section B Question 9

(a) month 2: 90; month 3: 93.6667; month 4: 99.6667; month 5: 104; month 6: 112.

Average each consecutive block of three values and place the result at the middle month.

(b) A time plot containing all seven raw points and the five centred averages at months 2 to 6, clearly distinguished and correctly scaled.

Plot time in order, align each average with its centre month, and distinguish the two series.

(c) The centred averages show an overall upward movement, with a small mid-series interruption. Seven observations are too few to establish a stable long-term trend or seasonality.

Interpret both the smoothing and the limited length of the investigation.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Average each consecutive block of three values and place the result at the middle month.; Carries the setup through the required calculation or representation for part a.; Obtains or justifies: month 2: 90; month 3: 93.6667; month 4: 99.6667; month 5: 104; month 6: 112..
  • Part b: Establishes a valid setup consistent with: Plot time in order, align each average with its centre month, and distinguish the two series.; Carries the setup through the required calculation or representation for part b.; Obtains or justifies: A time plot containing all seven raw points and the five centred averages at months 2 to 6, clearly distinguished and correctly scaled..
  • Part c: Establishes a valid setup consistent with: Interpret both the smoothing and the limited length of the investigation.; Carries the setup through the required calculation or representation for part c.; Obtains or justifies: The centred averages show an overall upward movement, with a small mid-series interruption. Seven observations are too few to establish a stable long-term trend or seasonality..

Detailed marking criteria

Part a (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Average each consecutive block of three values and place the result at the middle month.
  2. Carries the setup through the required calculation or representation for part a.
  3. Obtains or justifies: month 2: 90; month 3: 93.6667; month 4: 99.6667; month 5: 104; month 6: 112.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Plot time in order, align each average with its centre month, and distinguish the two series.
  2. Carries the setup through the required calculation or representation for part b.
  3. Obtains or justifies: A time plot containing all seven raw points and the five centred averages at months 2 to 6, clearly distinguished and correctly scaled.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Interpret both the smoothing and the limited length of the investigation.
  2. Carries the setup through the required calculation or representation for part c.
  3. Obtains or justifies: The centred averages show an overall upward movement, with a small mid-series interruption. Seven observations are too few to establish a stable long-term trend or seasonality.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section B Question 10

(a) Annual means: 93.05, 101.05, 109.05. Seasonal indices: Q1 0.776, Q2 1.089, Q3 1.312, Q4 0.823; mean = 1.000.

For each year, express every quarter as a proportion of that year's mean; then average the three corresponding quarterly proportions and check the index mean.

(b) Using the unrounded index 0.775752, deseasonalised value = 84.8 / 0.775752 = 109.3. This estimates the underlying trend-cycle level after removing the typical Q1 seasonal effect.

Divide the observed total by the matching unrounded seasonal index and explain that the seasonal component has been removed.

(c) Trend line: y-hat = 89.408 + 1.791t. Trend forecast at t = 13: 112.7. Reseasonalised Q1 forecast: 87.4. Both forecasts are rounded to one decimal place. The long-term trend and seasonal pattern are assumed to remain reasonably stable.

Regress deseasonalised value on time using unrounded indices, substitute the future time, multiply by the matching unrounded seasonal index, round both forecasts to one decimal place, and evaluate the stability assumption.

Mark allocation

  • Part a: Establishes a valid setup consistent with: For each year, express every quarter as a proportion of that year's mean; then average the three corresponding quarterly proportions and check the index mean.; Obtains or justifies: Annual means: 93.05, 101.05, 109.05. Seasonal indices: Q1 0.776, Q2 1.089, Q3 1.312, Q4 0.823; mean = 1.000..
  • Part b: Establishes a valid setup consistent with: Divide the observed total by the matching unrounded seasonal index and explain that the seasonal component has been removed.; Carries the setup through the required calculation or representation for part b.; Obtains or justifies: Using the unrounded index 0.775752, deseasonalised value = 84.8 / 0.775752 = 109.3. This estimates the underlying trend-cycle level after removing the typical Q1 seasonal effect..
  • Part c: Establishes a valid setup consistent with: Regress deseasonalised value on time using unrounded indices, substitute the future time, multiply by the matching unrounded seasonal index, round both forecasts to one decimal place, and evaluate the stability assumption.; Carries the setup through the required calculation or representation for part c.; Obtains or justifies: Trend line: y-hat = 89.408 + 1.791t. Trend forecast at t = 13: 112.7. Reseasonalised Q1 forecast: 87.4. Both forecasts are rounded to one decimal place. The long-term trend and seasonal pattern are assumed to remain reasonably stable..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: For each year, express every quarter as a proportion of that year's mean; then average the three corresponding quarterly proportions and check the index mean.
  2. Obtains or justifies: Annual means: 93.05, 101.05, 109.05. Seasonal indices: Q1 0.776, Q2 1.089, Q3 1.312, Q4 0.823; mean = 1.000.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Divide the observed total by the matching unrounded seasonal index and explain that the seasonal component has been removed.
  2. Carries the setup through the required calculation or representation for part b.
  3. Obtains or justifies: Using the unrounded index 0.775752, deseasonalised value = 84.8 / 0.775752 = 109.3. This estimates the underlying trend-cycle level after removing the typical Q1 seasonal effect.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Regress deseasonalised value on time using unrounded indices, substitute the future time, multiply by the matching unrounded seasonal index, round both forecasts to one decimal place, and evaluate the stability assumption.
  2. Carries the setup through the required calculation or representation for part c.
  3. Obtains or justifies: Trend line: y-hat = 89.408 + 1.791t. Trend forecast at t = 13: 112.7. Reseasonalised Q1 forecast: 87.4. Both forecasts are rounded to one decimal place. The long-term trend and seasonal pattern are assumed to remain reasonably stable.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section C Question 11

(a) A_n = 210 + 13(n - 1); G_n = 210(1.042)^(n - 1).

Represent constant and percentage growth correctly.

(b) A_6 = 275; G_6 is approximately 257.9633.

Evaluate both rules at n = 6.

(c) The arithmetic model is larger at period 6. Changing resources, capacity or participation can prevent either constant-change assumption from continuing.

Compare results and evaluate the modelling assumptions.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Represent constant and percentage growth correctly.; Carries the setup through the required calculation or representation for part a.; Obtains or justifies: A_n = 210 + 13(n - 1); G_n = 210(1.042)^(n - 1)..
  • Part b: Establishes a valid setup consistent with: Evaluate both rules at n = 6.; Carries the setup through the required calculation or representation for part b.; Obtains or justifies: A_6 = 275; G_6 is approximately 257.9633..
  • Part c: Establishes a valid setup consistent with: Compare results and evaluate the modelling assumptions.; Carries the setup through the required calculation or representation for part c.; Addresses the requested accuracy, unit, comparison or interpretation in: Identify which model is larger at period 6 and give one reason actual growth may follow neither model.; Obtains or justifies: The arithmetic model is larger at period 6. Changing resources, capacity or participation can prevent either constant-change assumption from continuing..

Detailed marking criteria

Part a (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Represent constant and percentage growth correctly.
  2. Carries the setup through the required calculation or representation for part a.
  3. Obtains or justifies: A_n = 210 + 13(n - 1); G_n = 210(1.042)^(n - 1).

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Evaluate both rules at n = 6.
  2. Carries the setup through the required calculation or representation for part b.
  3. Obtains or justifies: A_6 = 275; G_6 is approximately 257.9633.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (4 marks)

Award up to 4 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 2.0 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Compare results and evaluate the modelling assumptions.
  2. Carries the setup through the required calculation or representation for part c.
  3. Addresses the requested accuracy, unit, comparison or interpretation in: Identify which model is larger at period 6 and give one reason actual growth may follow neither model.
  4. Obtains or justifies: The arithmetic model is larger at period 6. Changing resources, capacity or participation can prevent either constant-change assumption from continuing.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section C Question 12

(a) r³ = 1.259712, so r = 1.08 and t_1 = 320.

Three ratio steps separate terms 2 and 5; take the positive cube root and back-divide once.

(b) Table values: 320.0, 345.6, 373.2, 403.1, 435.4, 470.2. Plot the six ordered pairs using term number horizontally.

Multiply successively by the recovered ratio and preserve the increasing curved pattern of the discrete points.

(c) t_n = 320(1.08)^(n - 1), and S_6 = 2347.5.

Use the geometric nth-term and finite-sum formulas with the recovered first term and ratio.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Three ratio steps separate terms 2 and 5; take the positive cube root and back-divide once.; Carries the setup through the required calculation or representation for part a.; Obtains or justifies: r³ = 1.259712, so r = 1.08 and t_1 = 320..
  • Part b: Establishes a valid setup consistent with: Multiply successively by the recovered ratio and preserve the increasing curved pattern of the discrete points.; Carries the setup through the required calculation or representation for part b.; Obtains or justifies: Table values: 320.0, 345.6, 373.2, 403.1, 435.4, 470.2. Plot the six ordered pairs using term number horizontally..
  • Part c: Establishes a valid setup consistent with: Use the geometric nth-term and finite-sum formulas with the recovered first term and ratio.; Carries the setup through the required calculation or representation for part c.; Obtains or justifies: t_n = 320(1.08)^(n - 1), and S_6 = 2347.5..

Detailed marking criteria

Part a (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Three ratio steps separate terms 2 and 5; take the positive cube root and back-divide once.
  2. Carries the setup through the required calculation or representation for part a.
  3. Obtains or justifies: r³ = 1.259712, so r = 1.08 and t_1 = 320.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Multiply successively by the recovered ratio and preserve the increasing curved pattern of the discrete points.
  2. Carries the setup through the required calculation or representation for part b.
  3. Obtains or justifies: Table values: 320.0, 345.6, 373.2, 403.1, 435.4, 470.2. Plot the six ordered pairs using term number horizontally.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Use the geometric nth-term and finite-sum formulas with the recovered first term and ratio.
  2. Carries the setup through the required calculation or representation for part c.
  3. Obtains or justifies: t_n = 320(1.08)^(n - 1), and S_6 = 2347.5.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section C Question 13

(a) t_1 = 36, t_(n+1) = t_n + 4; table values 36, 40, 44, 48, 52.

Use the initial value and add the common difference successively.

(b) The plotted points are (1, 36), (2, 40), (3, 44), (4, 48), (5, 52); the points are discrete.

Plot term number horizontally and term value vertically without presenting the sequence as continuous data.

(c) t_n = 36 + 4(n - 1); t_12 = 80; S_12 = 696.

Use the arithmetic nth-term rule and 12(first term + twelfth term) / 2.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Use the initial value and add the common difference successively.; Carries the setup through the required calculation or representation for part a.; Obtains or justifies: t_1 = 36, t_(n+1) = t_n + 4; table values 36, 40, 44, 48, 52..
  • Part b: Establishes a valid setup consistent with: Plot term number horizontally and term value vertically without presenting the sequence as continuous data.; Carries the setup through the required calculation or representation for part b.; Obtains or justifies: The plotted points are (1, 36), (2, 40), (3, 44), (4, 48), (5, 52); the points are discrete..
  • Part c: Establishes a valid setup consistent with: Use the arithmetic nth-term rule and 12(first term + twelfth term) / 2.; Carries the setup through the required calculation or representation for part c.; Obtains or justifies: t_n = 36 + 4(n - 1); t_12 = 80; S_12 = 696..

Detailed marking criteria

Part a (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Use the initial value and add the common difference successively.
  2. Carries the setup through the required calculation or representation for part a.
  3. Obtains or justifies: t_1 = 36, t_(n+1) = t_n + 4; table values 36, 40, 44, 48, 52.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Plot term number horizontally and term value vertically without presenting the sequence as continuous data.
  2. Carries the setup through the required calculation or representation for part b.
  3. Obtains or justifies: The plotted points are (1, 36), (2, 40), (3, 44), (4, 48), (5, 52); the points are discrete.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Use the arithmetic nth-term rule and 12(first term + twelfth term) / 2.
  2. Carries the setup through the required calculation or representation for part c.
  3. Obtains or justifies: t_n = 36 + 4(n - 1); t_12 = 80; S_12 = 696.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section C Question 14

(a) 70 = 82a + c and 62.8 = 70a + c, giving a = 0.6 and c = 20.8.

Subtract the equations to isolate the multiplier, then substitute to find the constant.

(b) u_5 = 54.33.

Continue the reconstructed recurrence through five updates from u_0.

(c) L = c / (1 - a) = 52. Because |a| < 1, the sequence converges to 52, approaching from above for the supplied initial value.

Solve the equilibrium equation and use the multiplier magnitude and initial position to classify convergence.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Subtract the equations to isolate the multiplier, then substitute to find the constant.; Obtains or justifies: 70 = 82a + c and 62.8 = 70a + c, giving a = 0.6 and c = 20.8..
  • Part b: Establishes a valid setup consistent with: Continue the reconstructed recurrence through five updates from u_0.; Carries the setup through the required calculation or representation for part b.; Obtains or justifies: u_5 = 54.33..
  • Part c: Establishes a valid setup consistent with: Solve the equilibrium equation and use the multiplier magnitude and initial position to classify convergence.; Carries the setup through the required calculation or representation for part c.; Obtains or justifies: L = c / (1 - a) = 52. Because |a| < 1, the sequence converges to 52, approaching from above for the supplied initial value..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Subtract the equations to isolate the multiplier, then substitute to find the constant.
  2. Obtains or justifies: 70 = 82a + c and 62.8 = 70a + c, giving a = 0.6 and c = 20.8.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Continue the reconstructed recurrence through five updates from u_0.
  2. Carries the setup through the required calculation or representation for part b.
  3. Obtains or justifies: u_5 = 54.33.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Solve the equilibrium equation and use the multiplier magnitude and initial position to classify convergence.
  2. Carries the setup through the required calculation or representation for part c.
  3. Obtains or justifies: L = c / (1 - a) = 52. Because |a| < 1, the sequence converges to 52, approaching from above for the supplied initial value.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section D Question 15

(a) A_1 = AUD 230.00; A_2 = AUD 460.94.

Apply the recurrence for the first two end-of-month deposits.

(b) A_n = 230[(1.0041)^n - 1] / (1.0041 - 1).

Recognise the accumulated deposits as a geometric series.

(c) A_12 = AUD 2,823.10.

Evaluate the annuity expression at n = 12.

(d) Annual withdrawal = AUD 1,062.50. The effective return must remain sufficient and fees, inflation and investment risk are ignored.

Use payment = principal x effective rate and identify the constant-return assumption.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Apply the recurrence for the first two end-of-month deposits.; Obtains or justifies: A_1 = AUD 230.00; A_2 = AUD 460.94..
  • Part b: Establishes a valid setup consistent with: Recognise the accumulated deposits as a geometric series.; Obtains or justifies: A_n = 230[(1.0041)^n - 1] / (1.0041 - 1)..
  • Part c: Establishes a valid setup consistent with: Evaluate the annuity expression at n = 12.; Obtains or justifies: A_12 = AUD 2,823.10..
  • Part d: Establishes a valid setup consistent with: Use payment = principal x effective rate and identify the constant-return assumption.; Carries the setup through the required calculation or representation for part d.; Obtains or justifies: Annual withdrawal = AUD 1,062.50. The effective return must remain sufficient and fees, inflation and investment risk are ignored..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Apply the recurrence for the first two end-of-month deposits.
  2. Obtains or justifies: A_1 = AUD 230.00; A_2 = AUD 460.94.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Recognise the accumulated deposits as a geometric series.
  2. Obtains or justifies: A_n = 230[(1.0041)^n - 1] / (1.0041 - 1).

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Evaluate the annuity expression at n = 12.
  2. Obtains or justifies: A_12 = AUD 2,823.10.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part d (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Use payment = principal x effective rate and identify the constant-return assumption.
  2. Carries the setup through the required calculation or representation for part d.
  3. Obtains or justifies: Annual withdrawal = AUD 1,062.50. The effective return must remain sufficient and fees, inflation and investment risk are ignored.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section D Question 16

(a) S_0 = A_0 = 32000; S_(n+1) = 1.0055S_n - 980; A_(n+1) = 1.0055A_n - 1160.

Use the common interest multiplier and each plan's end-of-month payment.

(b) Standard balance = AUD 27,109.18; accelerated balance = AUD 26,014.22; accelerated balance is AUD 1,094.96 lower.

Iterate both recurrences for exactly six complete cycles and compare balances on the same date.

(c) The accelerated plan saves AUD 14.96 in interest during the six months. Its earlier principal reductions lower later interest, so the balance benefit includes both extra payments and avoided interest.

Accumulate monthly interest from each opening balance and distinguish cash paid from interest avoided.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Use the common interest multiplier and each plan's end-of-month payment.; Carries the setup through the required calculation or representation for part a.; Obtains or justifies: S_0 = A_0 = 32000; S_(n+1) = 1.0055S_n - 980; A_(n+1) = 1.0055A_n - 1160..
  • Part b: Establishes a valid setup consistent with: Iterate both recurrences for exactly six complete cycles and compare balances on the same date.; Carries the setup through the required calculation or representation for part b.; Obtains or justifies: Standard balance = AUD 27,109.18; accelerated balance = AUD 26,014.22; accelerated balance is AUD 1,094.96 lower..
  • Part c: Establishes a valid setup consistent with: Accumulate monthly interest from each opening balance and distinguish cash paid from interest avoided.; Carries the setup through the required calculation or representation for part c.; Obtains or justifies: The accelerated plan saves AUD 14.96 in interest during the six months. Its earlier principal reductions lower later interest, so the balance benefit includes both extra payments and avoided interest..

Detailed marking criteria

Part a (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Use the common interest multiplier and each plan's end-of-month payment.
  2. Carries the setup through the required calculation or representation for part a.
  3. Obtains or justifies: S_0 = A_0 = 32000; S_(n+1) = 1.0055S_n - 980; A_(n+1) = 1.0055A_n - 1160.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Iterate both recurrences for exactly six complete cycles and compare balances on the same date.
  2. Carries the setup through the required calculation or representation for part b.
  3. Obtains or justifies: Standard balance = AUD 27,109.18; accelerated balance = AUD 26,014.22; accelerated balance is AUD 1,094.96 lower.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Accumulate monthly interest from each opening balance and distinguish cash paid from interest avoided.
  2. Carries the setup through the required calculation or representation for part c.
  3. Obtains or justifies: The accelerated plan saves AUD 14.96 in interest during the six months. Its earlier principal reductions lower later interest, so the balance benefit includes both extra payments and avoided interest.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section D Question 17

(a) Annual depreciation = AUD 3,600.00 and V_n = 36000 - 3600n.

Subtract the year-1 value from cost, then express repeated equal depreciation.

(b) Retained proportion = 0.82, so depreciation rate = 18% and R_n = 36000(0.82)^n.

Divide the year-1 value by cost, then convert retained proportion to a depreciation percentage.

(c) Straight-line value = AUD 18,000.00; reducing-balance value = AUD 13,346.63.

Evaluate each recovered model at the same year.

(d) The reducing-balance method records more accumulated depreciation; the book-value difference is AUD 4,653.37.

The lower book value corresponds to greater accumulated depreciation; subtract the values.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Subtract the year-1 value from cost, then express repeated equal depreciation.; Obtains or justifies: Annual depreciation = AUD 3,600.00 and V_n = 36000 - 3600n..
  • Part b: Establishes a valid setup consistent with: Divide the year-1 value by cost, then convert retained proportion to a depreciation percentage.; Obtains or justifies: Retained proportion = 0.82, so depreciation rate = 18% and R_n = 36000(0.82)^n..
  • Part c: Establishes a valid setup consistent with: Evaluate each recovered model at the same year.; Carries the setup through the required calculation or representation for part c.; Obtains or justifies: Straight-line value = AUD 18,000.00; reducing-balance value = AUD 13,346.63..
  • Part d: Establishes a valid setup consistent with: The lower book value corresponds to greater accumulated depreciation; subtract the values.; Carries the setup through the required calculation or representation for part d.; Obtains or justifies: The reducing-balance method records more accumulated depreciation; the book-value difference is AUD 4,653.37..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Subtract the year-1 value from cost, then express repeated equal depreciation.
  2. Obtains or justifies: Annual depreciation = AUD 3,600.00 and V_n = 36000 - 3600n.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Divide the year-1 value by cost, then convert retained proportion to a depreciation percentage.
  2. Obtains or justifies: Retained proportion = 0.82, so depreciation rate = 18% and R_n = 36000(0.82)^n.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Evaluate each recovered model at the same year.
  2. Carries the setup through the required calculation or representation for part c.
  3. Obtains or justifies: Straight-line value = AUD 18,000.00; reducing-balance value = AUD 13,346.63.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part d (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: The lower book value corresponds to greater accumulated depreciation; subtract the values.
  2. Carries the setup through the required calculation or representation for part d.
  3. Obtains or justifies: The reducing-balance method records more accumulated depreciation; the book-value difference is AUD 4,653.37.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section D Question 18

(a) M: 0.400% per month, 12 periods per year. Q: 1.225% per quarter, 4 periods per year.

Convert both nominal annual rates using the matching compounding frequency.

(b) M: 4.907% effective p.a.; Q: 4.991% effective p.a. Offer Q is greater.

Compound each periodic rate for one year before comparing the offers.

(c) Future value = AUD 10,415.88. This assumes the advertised rate and compounding arrangement remain unchanged and ignores fees and tax.

Use the selected periodic rate for all compounding periods over three years, then evaluate the product conditions.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Convert both nominal annual rates using the matching compounding frequency.; Obtains or justifies: M: 0.400% per month, 12 periods per year. Q: 1.225% per quarter, 4 periods per year..
  • Part b: Establishes a valid setup consistent with: Compound each periodic rate for one year before comparing the offers.; Carries the setup through the required calculation or representation for part b.; Obtains or justifies: M: 4.907% effective p.a.; Q: 4.991% effective p.a. Offer Q is greater..
  • Part c: Establishes a valid setup consistent with: Use the selected periodic rate for all compounding periods over three years, then evaluate the product conditions.; Carries the setup through the required calculation or representation for part c.; Obtains or justifies: Future value = AUD 10,415.88. This assumes the advertised rate and compounding arrangement remain unchanged and ignores fees and tax..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Convert both nominal annual rates using the matching compounding frequency.
  2. Obtains or justifies: M: 0.400% per month, 12 periods per year. Q: 1.225% per quarter, 4 periods per year.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Compound each periodic rate for one year before comparing the offers.
  2. Carries the setup through the required calculation or representation for part b.
  3. Obtains or justifies: M: 4.907% effective p.a.; Q: 4.991% effective p.a. Offer Q is greater.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Use the selected periodic rate for all compounding periods over three years, then evaluate the product conditions.
  2. Carries the setup through the required calculation or representation for part c.
  3. Obtains or justifies: Future value = AUD 10,415.88. This assumes the advertised rate and compounding arrangement remain unchanged and ignores fees and tax.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section E Question 19

(a) Row minima: 2, 3, 1, 4. Row-reduced matrix: A [7, 0, 5, 6]; B [3, 1, 0, 4]; C [4, 7, 0, 7]; D [3, 2, 5, 0].

Subtract the smallest entry in each row from every entry in that row.

(b) Column minima after row reduction: 3, 0, 0, 0. Reduced matrix: A [4, 0, 5, 6]; B [0, 1, 0, 4]; C [1, 7, 0, 7]; D [0, 2, 5, 0]. Independent zeros can be selected at A-2, B-1, C-3 and D-4.

Subtract each column minimum, then choose one zero in every row and every column.

(c) Assign A to 2, B to 1, C to 3 and D to 4. Minimum total cost = 13.

Return to the original costs and add the four entries selected by the independent-zero assignment.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Subtract the smallest entry in each row from every entry in that row.; Obtains or justifies: Row minima: 2, 3, 1, 4. Row-reduced matrix: A [7, 0, 5, 6]; B [3, 1, 0, 4]; C [4, 7, 0, 7]; D [3, 2, 5, 0]..
  • Part b: Establishes a valid setup consistent with: Subtract each column minimum, then choose one zero in every row and every column.; Obtains or justifies: Column minima after row reduction: 3, 0, 0, 0. Reduced matrix: A [4, 0, 5, 6]; B [0, 1, 0, 4]; C [1, 7, 0, 7]; D [0, 2, 5, 0]. Independent zeros can be selected at A-2, B-1, C-3 and D-4..
  • Part c: Establishes a valid setup consistent with: Return to the original costs and add the four entries selected by the independent-zero assignment.; Obtains or justifies: Assign A to 2, B to 1, C to 3 and D to 4. Minimum total cost = 13..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Subtract the smallest entry in each row from every entry in that row.
  2. Obtains or justifies: Row minima: 2, 3, 1, 4. Row-reduced matrix: A [7, 0, 5, 6]; B [3, 1, 0, 4]; C [4, 7, 0, 7]; D [3, 2, 5, 0].

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Subtract each column minimum, then choose one zero in every row and every column.
  2. Obtains or justifies: Column minima after row reduction: 3, 0, 0, 0. Reduced matrix: A [4, 0, 5, 6]; B [0, 1, 0, 4]; C [1, 7, 0, 7]; D [0, 2, 5, 0]. Independent zeros can be selected at A-2, B-1, C-3 and D-4.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Return to the original costs and add the four entries selected by the independent-zero assignment.
  2. Obtains or justifies: Assign A to 2, B to 1, C to 3 and D to 4. Minimum total cost = 13.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section E Question 20

(a) A-B-C-D-E, with total length 10.

Compare viable routes; A-B-C-D-E has length 1 + 2 + 3 + 4 = 10.

(b) A-B-D-E, with total length 12. The original route requires the closed edge C-D, so it is infeasible.

Remove the unavailable edge, compare the remaining complete routes, and justify the selected alternative.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Compare viable routes; A-B-C-D-E has length 1 + 2 + 3 + 4 = 10.; Carries the setup through the required calculation or representation for part a.; Obtains or justifies: A-B-C-D-E, with total length 10..
  • Part b: Establishes a valid setup consistent with: Remove the unavailable edge, compare the remaining complete routes, and justify the selected alternative.; Carries the setup through the required calculation or representation for part b.; Addresses the requested accuracy, unit, comparison or interpretation in: Edge C-D closes. Find the new shortest route from A to E and explain why the original route can no longer be used.; Obtains or justifies: A-B-D-E, with total length 12. The original route requires the closed edge C-D, so it is infeasible..

Detailed marking criteria

Part a (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Compare viable routes; A-B-C-D-E has length 1 + 2 + 3 + 4 = 10.
  2. Carries the setup through the required calculation or representation for part a.
  3. Obtains or justifies: A-B-C-D-E, with total length 10.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (4 marks)

Award up to 4 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 2.0 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Remove the unavailable edge, compare the remaining complete routes, and justify the selected alternative.
  2. Carries the setup through the required calculation or representation for part b.
  3. Addresses the requested accuracy, unit, comparison or interpretation in: Edge C-D closes. Find the new shortest route from A to E and explain why the original route can no longer be used.
  4. Obtains or justifies: A-B-D-E, with total length 12. The original route requires the closed edge C-D, so it is infeasible.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section E Question 21

(a) AB, BC, CD and DE.

Select the least available edge that joins a new vertex without forming a cycle.

(b) Total weight = 18. The path edges connect all five vertices without a cycle, while each diagonal is heavier than the corresponding connection already available.

Add the four selected weights and justify exclusion by the cut or cycle property.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Select the least available edge that joins a new vertex without forming a cycle.; Carries the setup through the required calculation or representation for part a.; Addresses the requested accuracy, unit, comparison or interpretation in: Use Prim's algorithm to list the edges in one minimum spanning tree.; Obtains or justifies: AB, BC, CD and DE..
  • Part b: Establishes a valid setup consistent with: Add the four selected weights and justify exclusion by the cut or cycle property.; Carries the setup through the required calculation or representation for part b.; Addresses the requested accuracy, unit, comparison or interpretation in: Find the total weight and explain why the three longer diagonal edges are excluded.; Obtains or justifies: Total weight = 18. The path edges connect all five vertices without a cycle, while each diagonal is heavier than the corresponding connection already available..

Detailed marking criteria

Part a (4 marks)

Award up to 4 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 2.0 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Select the least available edge that joins a new vertex without forming a cycle.
  2. Carries the setup through the required calculation or representation for part a.
  3. Addresses the requested accuracy, unit, comparison or interpretation in: Use Prim's algorithm to list the edges in one minimum spanning tree.
  4. Obtains or justifies: AB, BC, CD and DE.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (4 marks)

Award up to 4 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 2.0 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Add the four selected weights and justify exclusion by the cut or cycle property.
  2. Carries the setup through the required calculation or representation for part b.
  3. Addresses the requested accuracy, unit, comparison or interpretation in: Find the total weight and explain why the three longer diagonal edges are excluded.
  4. Obtains or justifies: Total weight = 18. The path edges connect all five vertices without a cycle, while each diagonal is heavier than the corresponding connection already available.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section E Question 22

(a) EST(C) = 3, EST(D) = 3, EST(E) = 5, EST(F) = 10; minimum duration = 13 days.

Start A and B at zero; for each later activity use the largest completion time among its immediate predecessors.

(b) LST(A) = 0, LST(B) = 0, LST(C) = 6, LST(D) = 3, LST(E) = 5, LST(F) = 10.

Begin from the project finish and subtract durations, using the smallest allowable successor start at a merge.

(c) Floats: A 0, B 0, C 3, D 0, E 0, F 0 day(s). Critical path: A-B-D-E-F; project duration: 13 days.

Calculate LST minus EST for every activity; the zero-float activities form the critical path.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Start A and B at zero; for each later activity use the largest completion time among its immediate predecessors.; Obtains or justifies: EST(C) = 3, EST(D) = 3, EST(E) = 5, EST(F) = 10; minimum duration = 13 days..
  • Part b: Establishes a valid setup consistent with: Begin from the project finish and subtract durations, using the smallest allowable successor start at a merge.; Obtains or justifies: LST(A) = 0, LST(B) = 0, LST(C) = 6, LST(D) = 3, LST(E) = 5, LST(F) = 10..
  • Part c: Establishes a valid setup consistent with: Calculate LST minus EST for every activity; the zero-float activities form the critical path.; Carries the setup through the required calculation or representation for part c.; Obtains or justifies: Floats: A 0, B 0, C 3, D 0, E 0, F 0 day(s). Critical path: A-B-D-E-F; project duration: 13 days..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Start A and B at zero; for each later activity use the largest completion time among its immediate predecessors.
  2. Obtains or justifies: EST(C) = 3, EST(D) = 3, EST(E) = 5, EST(F) = 10; minimum duration = 13 days.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Begin from the project finish and subtract durations, using the smallest allowable successor start at a merge.
  2. Obtains or justifies: LST(A) = 0, LST(B) = 0, LST(C) = 6, LST(D) = 3, LST(E) = 5, LST(F) = 10.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Calculate LST minus EST for every activity; the zero-float activities form the critical path.
  2. Carries the setup through the required calculation or representation for part c.
  3. Obtains or justifies: Floats: A 0, B 0, C 3, D 0, E 0, F 0 day(s). Critical path: A-B-D-E-F; project duration: 13 days.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section E Question 23

(a) Send 4 units on S-A-T and 5 units on S-B-T. All capacities and flow conservation conditions are satisfied.

Allocate flow on complete source-to-sink paths and verify capacity and conservation.

(b) The cut immediately before T contains A-T with capacity 4 and B-T with capacity 5, so its capacity is 9. A feasible flow of 9 therefore equals the minimum cut and is maximum.

Calculate the cut capacity and invoke the maximum-flow minimum-cut result.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Allocate flow on complete source-to-sink paths and verify capacity and conservation.; Carries the setup through the required calculation or representation for part a.; Addresses the requested accuracy, unit, comparison or interpretation in: Give a feasible flow of value 9 from S to T.; Obtains or justifies: Send 4 units on S-A-T and 5 units on S-B-T. All capacities and flow conservation conditions are satisfied..
  • Part b: Establishes a valid setup consistent with: Calculate the cut capacity and invoke the maximum-flow minimum-cut result.; Carries the setup through the required calculation or representation for part b.; Addresses the requested accuracy, unit, comparison or interpretation in: Identify a cut that proves the flow is maximum.; Obtains or justifies: The cut immediately before T contains A-T with capacity 4 and B-T with capacity 5, so its capacity is 9. A feasible flow of 9 therefore equals the minimum cut and is maximum..

Detailed marking criteria

Part a (4 marks)

Award up to 4 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 2.0 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Allocate flow on complete source-to-sink paths and verify capacity and conservation.
  2. Carries the setup through the required calculation or representation for part a.
  3. Addresses the requested accuracy, unit, comparison or interpretation in: Give a feasible flow of value 9 from S to T.
  4. Obtains or justifies: Send 4 units on S-A-T and 5 units on S-B-T. All capacities and flow conservation conditions are satisfied.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (4 marks)

Award up to 4 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 2.0 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Calculate the cut capacity and invoke the maximum-flow minimum-cut result.
  2. Carries the setup through the required calculation or representation for part b.
  3. Addresses the requested accuracy, unit, comparison or interpretation in: Identify a cut that proves the flow is maximum.
  4. Obtains or justifies: The cut immediately before T contains A-T with capacity 4 and B-T with capacity 5, so its capacity is 9. A feasible flow of 9 therefore equals the minimum cut and is maximum.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section E Question 24

(a) Eastward component = 27.47 km; northward component = 5.99 km.

For each leg use east = distance sin(bearing) and north = distance cos(bearing), then add corresponding components.

(b) Distance = 28.12 km.

Apply Pythagoras' theorem to the total east and north components.

(c) True bearing = 078 degrees. Both component signs place the displacement in the corresponding compass quadrant, confirming the atan2 bearing.

Measure clockwise from north using atan2(east, north) and verify the result from the displacement signs.

Mark allocation

  • Part a: Establishes a valid setup consistent with: For each leg use east = distance sin(bearing) and north = distance cos(bearing), then add corresponding components.; Obtains or justifies: Eastward component = 27.47 km; northward component = 5.99 km..
  • Part b: Establishes a valid setup consistent with: Apply Pythagoras' theorem to the total east and north components.; Carries the setup through the required calculation or representation for part b.; Obtains or justifies: Distance = 28.12 km..
  • Part c: Establishes a valid setup consistent with: Measure clockwise from north using atan2(east, north) and verify the result from the displacement signs.; Carries the setup through the required calculation or representation for part c.; Obtains or justifies: True bearing = 078 degrees. Both component signs place the displacement in the corresponding compass quadrant, confirming the atan2 bearing..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: For each leg use east = distance sin(bearing) and north = distance cos(bearing), then add corresponding components.
  2. Obtains or justifies: Eastward component = 27.47 km; northward component = 5.99 km.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Apply Pythagoras' theorem to the total east and north components.
  2. Carries the setup through the required calculation or representation for part b.
  3. Obtains or justifies: Distance = 28.12 km.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Measure clockwise from north using atan2(east, north) and verify the result from the displacement signs.
  2. Carries the setup through the required calculation or representation for part c.
  3. Obtains or justifies: True bearing = 078 degrees. Both component signs place the displacement in the corresponding compass quadrant, confirming the atan2 bearing.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section E Question 25

(a) 5020 km.

Multiply Earth's radius by cosine of the latitude.

(b) 526 km.

Take the longitude fraction of the parallel circumference.

(c) Approximately 45 minutes. Real routes, wind and speed changes are ignored.

Convert distance to time and evaluate the constant-speed spherical model.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Multiply Earth's radius by cosine of the latitude.; Obtains or justifies: 5020 km..
  • Part b: Establishes a valid setup consistent with: Take the longitude fraction of the parallel circumference.; Carries the setup through the required calculation or representation for part b.; Obtains or justifies: 526 km..
  • Part c: Establishes a valid setup consistent with: Convert distance to time and evaluate the constant-speed spherical model.; Carries the setup through the required calculation or representation for part c.; Obtains or justifies: Approximately 45 minutes. Real routes, wind and speed changes are ignored..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Multiply Earth's radius by cosine of the latitude.
  2. Obtains or justifies: 5020 km.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Take the longitude fraction of the parallel circumference.
  2. Carries the setup through the required calculation or representation for part b.
  3. Obtains or justifies: 526 km.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Convert distance to time and evaluate the constant-speed spherical model.
  2. Carries the setup through the required calculation or representation for part c.
  3. Obtains or justifies: Approximately 45 minutes. Real routes, wind and speed changes are ignored.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section E Question 26

(a) A triangle with adjacent sides labelled 7.2 km and 9.3 km, their included angle labelled 52 degrees, and the opposite side labelled c.

Create a consistent triangle representation with every supplied quantity placed at the correct side or angle.

(b) c = 7.48 km.

Apply the cosine rule using the included angle.

(c) 26.38 square kilometres.

Use one-half times the two known sides times sine of the included angle.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Create a consistent triangle representation with every supplied quantity placed at the correct side or angle.; Obtains or justifies: A triangle with adjacent sides labelled 7.2 km and 9.3 km, their included angle labelled 52 degrees, and the opposite side labelled c..
  • Part b: Establishes a valid setup consistent with: Apply the cosine rule using the included angle.; Obtains or justifies: c = 7.48 km..
  • Part c: Establishes a valid setup consistent with: Use one-half times the two known sides times sine of the included angle.; Carries the setup through the required calculation or representation for part c.; Obtains or justifies: 26.38 square kilometres..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Create a consistent triangle representation with every supplied quantity placed at the correct side or angle.
  2. Obtains or justifies: A triangle with adjacent sides labelled 7.2 km and 9.3 km, their included angle labelled 52 degrees, and the opposite side labelled c.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Apply the cosine rule using the included angle.
  2. Obtains or justifies: c = 7.48 km.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Use one-half times the two known sides times sine of the included angle.
  2. Carries the setup through the required calculation or representation for part c.
  3. Obtains or justifies: 26.38 square kilometres.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section E Question 27

(a) Departure: Wed 14 Oct 09:20 UTC. City B arrival: Thu 15 Oct 02:40 local time.

Subtract the City A offset, add the first-flight duration in UTC, then apply the City B offset while retaining the date.

(b) City B departure: Thu 15 Oct 04:25 local time; Wed 14 Oct 16:25 UTC.

Add the stopover in City B local time, then subtract twelve hours to return to UTC.

(c) City C arrival: Wed 14 Oct 15:35 local time. Total elapsed time: 14 h 15 min. The calculation assumes the stated fixed offsets and scheduled flight and stopover durations apply without delay.

Add the second flight in UTC, apply UTC-8 to obtain the correct date across the International Date Line, and compare UTC departure and arrival instants for elapsed time.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Subtract the City A offset, add the first-flight duration in UTC, then apply the City B offset while retaining the date.; Obtains or justifies: Departure: Wed 14 Oct 09:20 UTC. City B arrival: Thu 15 Oct 02:40 local time..
  • Part b: Establishes a valid setup consistent with: Add the stopover in City B local time, then subtract twelve hours to return to UTC.; Obtains or justifies: City B departure: Thu 15 Oct 04:25 local time; Wed 14 Oct 16:25 UTC..
  • Part c: Establishes a valid setup consistent with: Add the second flight in UTC, apply UTC-8 to obtain the correct date across the International Date Line, and compare UTC departure and arrival instants for elapsed time.; Carries the setup through the required calculation or representation for part c.; Obtains or justifies: City C arrival: Wed 14 Oct 15:35 local time. Total elapsed time: 14 h 15 min. The calculation assumes the stated fixed offsets and scheduled flight and stopover durations apply without delay..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Subtract the City A offset, add the first-flight duration in UTC, then apply the City B offset while retaining the date.
  2. Obtains or justifies: Departure: Wed 14 Oct 09:20 UTC. City B arrival: Thu 15 Oct 02:40 local time.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Add the stopover in City B local time, then subtract twelve hours to return to UTC.
  2. Obtains or justifies: City B departure: Thu 15 Oct 04:25 local time; Wed 14 Oct 16:25 UTC.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (3 marks)

Award up to 3 marks in 0.5-mark increments for the demonstrated checkpoints. A correct answer with no relevant working receives a maximum of 1.5 marks; incorrect or incomplete answers may receive partial credit for correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Add the second flight in UTC, apply UTC-8 to obtain the correct date across the International Date Line, and compare UTC departure and arrival instants for elapsed time.
  2. Carries the setup through the required calculation or representation for part c.
  3. Obtains or justifies: City C arrival: Wed 14 Oct 15:35 local time. Total elapsed time: 14 h 15 min. The calculation assumes the stated fixed offsets and scheduled flight and stopover durations apply without delay.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Section E Question 28

(a) The horizontal lines through the observer and each boat are parallel, so the alternate interior angles are equal.

Connect the horizontal sight reference lines using parallel-line angle facts.

(b) P: 71.9 m; Q: 51.2 m.

Use tangent with platform height opposite and horizontal distance adjacent for each right triangle.

(c) Distance PQ = 20.7 m. The boats and platform base are assumed collinear on the same side of the platform.

Subtract the two horizontal distances only after identifying the shared straight bearing and side.

Mark allocation

  • Part a: Establishes a valid setup consistent with: Connect the horizontal sight reference lines using parallel-line angle facts.; Obtains or justifies: The horizontal lines through the observer and each boat are parallel, so the alternate interior angles are equal..
  • Part b: Establishes a valid setup consistent with: Use tangent with platform height opposite and horizontal distance adjacent for each right triangle.; Obtains or justifies: P: 71.9 m; Q: 51.2 m..
  • Part c: Establishes a valid setup consistent with: Subtract the two horizontal distances only after identifying the shared straight bearing and side.; Obtains or justifies: Distance PQ = 20.7 m. The boats and platform base are assumed collinear on the same side of the platform..

Detailed marking criteria

Part a (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Connect the horizontal sight reference lines using parallel-line angle facts.
  2. Obtains or justifies: The horizontal lines through the observer and each boat are parallel, so the alternate interior angles are equal.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part b (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Use tangent with platform height opposite and horizontal distance adjacent for each right triangle.
  2. Obtains or justifies: P: 71.9 m; Q: 51.2 m.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Part c (2 marks)

Award 2 marks for a correct answer with relevant working. A correct answer with no working receives a maximum of 1.5 marks. Award partial credit in 0.5-mark increments for demonstrated correct progress.

Indicative checkpoints (0.5-mark increments allowed):

  1. Establishes a valid setup consistent with: Subtract the two horizontal distances only after identifying the shared straight bearing and side.
  2. Obtains or justifies: Distance PQ = 20.7 m. The boats and platform base are assumed collinear on the same side of the platform.

Acceptable alternatives: Accept mathematically equivalent working, notation and correctly rounded values that satisfy the task.

Do not credit by itself: Using an operation or denominator that does not match the supplied model. Reporting a numerical result without the requested unit, accuracy or contextual interpretation.

Diagnostic Checklist

TopicQuestionsMarksMarks LostAction
Criterion 3 - Mathematical and Statistical Models Q1-Q6 36 ___ Review model selection, calculation, assumptions, limitations and contextual interpretation across data, sequence and finance models.
Criterion 5 - Bivariate Data Analysis Q7-Q10 36 ___ Review constructed statistical and residual plots, linear-model appropriateness, r and r-squared, categorical association, moving averages, average-percentage seasonal indices, deseasonalisation, least-squares time trends, forecast reliability and contextual conclusions.
Criterion 6 - Growth and Decay in Sequences Q11-Q14 36 ___ Review arithmetic and geometric tables and graphs, explicit and recurrence rules, sums, steady values and model comparison.
Criterion 7 - Finance Q15-Q18 36 ___ Review compound interest, effective rates, reducing-balance loans, annuities, perpetuities, and straight-line and reducing-balance depreciation.
Criterion 8 - Selected Section E alternative Q19-Q28 36 ___ Review only the attempted alternative: network optimisation and decision mathematics, or labelled two-dimensional sketches, trigonometry and Earth geometry.

What is included

Full Practice Examination Showcase questions (180 marks)

Links to the current official examination resources supplied separately by the assessment authority

Worked solutions and marking guidance shown online

Diagnostic checklist shown online

Free browser viewing with no checkout

No PDF or downloadable file

How to use this pack

  1. Attempt: Open the complete paper online and work under the timing and conditions shown on this page.
  2. Mark: Use the supplied worked solutions or response support and marking guidance to check answers and method.
  3. Review: Use the supplied diagnostic or review support to identify the next areas for revision.

Is this pack right for you?

Designed for

Students, parents, teachers and tutors who want to inspect a complete online TASC General Mathematics Level 3 example before choosing a released PDF pack.

Product at a glance

  • TASC General Mathematics Level 3
  • 2026 edition · Pack 0 · v2.0
  • 1 online paper
  • Free online view · no checkout or PDF download
  • Free to view online
  • No monthly Online Practice subscription required

Compare before buying

Pack 0 is the free online showcase for this course. Other pack numbers identify separate original products; they do not indicate difficulty or a required order.

Official examination resources

Open these current official resources alongside the Skill Align paper. They remain hosted and controlled by the assessment authority and are not republished by Skill Align.

Current TASC General Mathematics Level 3 course Official current course, module and content reference.
Current MTG315123 external-assessment specifications Official written-examination structure and marking conditions.
Current TASC General Mathematics Information Sheet Official TASC resource, Version 2, February 2026. Supply this sheet for the practice examination.
2025 TASC General Mathematics examination paper Official prior paper used only for structural calibration; no question wording is copied.

Questions about this exam pack

What is included in General Mathematics Level 3 Free Online - Pack 0?

Pack 0 includes one full-length showcase paper, worked solutions, marking guidance and diagnostic checklists, all shown online.

Is Pack 0 really free?

Yes. Pack 0 can be read online without checkout or a monthly subscription.

What does Pack 0 mean?

Pack 0 identifies the free online showcase for this course. Other pack numbers identify separate original products; they do not indicate difficulty or a required completion order.

Can I download Pack 0 as a PDF?

No. Pack 0 is intentionally online-only and no downloadable PDF is provided.

Are these official assessment authority examination questions?

No. The questions are original Skill Align material. Skill Align is independent and is not affiliated with, authorised by, sponsored by, approved by, or endorsed by any state assessment authority.

Independent practice resource

TASC courses, assessment and certification are administered by the Tasmanian Assessment, Standards and Certification office. Skill Align is an independent publisher and is not affiliated with, authorised by, sponsored by, approved by, or endorsed by TASC or the Tasmanian Government. Skill Align packs are original practice resources and do not reproduce official TASC examination content.

Each exam pack is listed with a pack label so buyers can distinguish separate original products in the same course series. Pack numbers do not indicate difficulty or a required completion order.