Skill Align TASC Essential Mathematics Level 2 Personal + Workplace Dual-course Free Online Pack 0 - 2026 Edition
Original Skill Align practice-assessment material covering selected content from two separate TASC courses: Essential Mathematics - Personal Level 2 (MEP215123) and Essential Mathematics - Workplace Level 2 (MEW215123). This booklet is not a complete assessment for either course. Learners enrolled in only one course should complete the relevant labelled section.
- Paper
- Question and Response Booklet Showcase
- Reading
- As directed by the supervising teacher
- Writing
- Full dual-course compilation: 120 minutes; Suggested Personal section only: approximately 55 minutes; Suggested Workplace section only: approximately 65 minutes
- Assessment
- 90 marks
Skill Align practice conditions: a scientific calculator is permitted; a ruler and scale ruler are permitted where required; internet access and external communication are not permitted; no spreadsheet software is required because every spreadsheet-style table is supplied in this booklet; no reference sheet is supplied; a graphics calculator or CAS may be used only when the supervising teacher explicitly permits it. No public PDF download is supplied with Pack 0.
Essential Mathematics - Personal Level 2 (MEP215123) - 40 marks
Complete Questions 1-4 only if you are using the Personal course section. Suggested section-only working time is approximately 55 minutes. The supervising teacher may adjust this practice timing. Show method selection, working, units, interpretation and justification when the instruction requests them.
Question 1
10 marksQuestion 2
10 marksQuestion 3
10 marksQuestion 4
10 marksEssential Mathematics - Workplace Level 2 (MEW215123) - 50 marks
Complete Questions 5-9 only if you are using the Workplace course section. Suggested section-only working time is approximately 65 minutes. The supervising teacher may adjust this practice timing. Show practical calculations, units, representations and decisions requested in each part.
Question 5
10 marksQuestion 6
10 marksQuestion 7
10 marksQuestion 8
10 marksQuestion 9
10 marksWorked Solutions And Marking Guide
Question 1
(a) $3986.67 per month.
Annual income is 920 × 52=$47,840. Monthly income is 47,840 / 12=$3986.666ldots, so $3986.67.
(b) $886.67.
Car transport costs total 380+220+160+70=$830. Total expenses are 1240+520+210+300+830=$3100. The surplus is 3986.67-3100=$886.67.
(c) The public-transport surplus is $1526.67, which is $640.00 more than the car-option surplus. Public transport is preferable on the supplied financial data; availability, travel time, accessibility or reliability is a relevant non-financial consideration.
Public-transport expenses are 1240+520+210+300+190=$2460, so the surplus is 3986.67-2460=$1526.67. The difference is 1526.67-886.67=$640.00.
Detailed marking criteria
Part a (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: calculates annual income 920 × 52=$47,840; divides the annual income by 12; states $3986.67 per month. Accept $3986.67; allow $3986.66 only when the candidate explicitly truncates rather than rounds. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Acceptable alternatives: an equivalent calculation using 920 × 52 / 12
Do not credit by itself: a response that omits the required evidence for convert weekly income to a monthly spreadsheet input; an unsupported final answer with no assessable calculation or interpretation
Part b (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: totals the four car costs as $830; totals all car-option expenses as $3100; subtracts expenses from income to obtain a $886.67 surplus. Accept $886.67 to the nearest cent. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: omitting registration, insurance or maintenance; adding the surplus to expenses
Part c (4 marks)
Award one mark for each observable checkpoint, to a maximum of 4: totals public-transport expenses as $2460; calculates the public-transport surplus as $1526.67; calculates the surplus advantage as $640.00; recommends public transport on financial grounds and identifies one relevant non-financial consideration. Accept money values within one cent and any context-relevant non-financial consideration. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Acceptable alternatives: a car recommendation supported by a clearly stated non-financial priority despite its lower supplied surplus
Do not credit by itself: a response that omits the required evidence for compare budget options and justify a practical recommendation; an unsupported final answer with no assessable calculation or interpretation
Question 2
(a) There is a strong negative, approximately linear association.
As activity hours increase, resting heart rate decreases. The points lie close to a straight-line pattern.
(b) yapprox-2.8x+83.6.
The gradient is (64-78) / (7-2)=-14 / 5=-2.8. Using (2,78), b=78-(-2.8)(2)=83.6.
(c) The prediction is 68.2 beats per minute. It is an interpolation for a participant with 5.5 weekly activity hours; other variables may affect heart rate, so association alone does not prove causation.
Substitute x=5.5: y=-2.8(5.5)+83.6=68.2. The value lies inside the observed activity range.
Detailed marking criteria
Part a (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: states that the direction is negative; states that the form is approximately linear; states that the association is strong. Accept equivalent statistical language; no numerical tolerance is required. Do not apply consequential marking because this part is independently determined from the supplied information.
Do not credit by itself: claiming that the association proves activity caused the lower heart rate
Part b (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: calculates the change in heart rate as -14 and activity as 5; obtains m=-2.8 beats per minute per activity hour; substitutes a point to obtain b=83.6. Accept m and b within 0.1 when supported by the stated endpoint method. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Acceptable alternatives: an equivalent two-point equation converted to slope-intercept form
Do not credit by itself: a response that omits the required evidence for calculate and interpret a fitted line from two data points; an unsupported final answer with no assessable calculation or interpretation
Part c (4 marks)
Award one mark for each observable checkpoint, to a maximum of 4: substitutes x=5.5 into the fitted model; calculates 68.2 beats per minute; identifies the prediction as interpolation within the observed range; states that uncontrolled variables or observational data prevent a causal conclusion. Accept 68 to 68.5 beats per minute if the candidate used a defensible rounded fitted line. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: treating the model as an exact biological rule; stating causation without experimental evidence
Question 3
(a) Estimated maximum =178 beats per minute. The target range is 115.7 to 142.4 beats per minute, or about 116 to 142 beats per minute.
220-42=178. Then 0.65(178)=115.7 and 0.80(178)=142.4.
(b) The immediate rate is 48(3)=144 beats per minute. It is 1.6 beats per minute above the unrounded upper target limit, so it is just above the target range.
There are three 20-second intervals in one minute. Compare 144 with the upper limit 142.4.
(c) At two minutes the pulse is 39(3)=117 beats per minute, so this is the first recorded time within the target range. The average rate of decrease over six minutes is (144-78) / 6=11 beats per minute per minute. The 220-age rule and short manual counts are estimates and do not capture individual fitness or measurement variation.
Convert each count by multiplying by 3. Average rate of decrease =(144-78) / 6=11 beats per minute per minute.
Detailed marking criteria
Part a (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: calculates maximum heart rate 178 beats per minute; calculates lower limit 115.7 beats per minute; calculates upper limit 142.4 beats per minute. Accept the target range rounded to 116-142 beats per minute when the unrounded limits are shown. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: a response that omits the required evidence for calculate percentage limits for a target rate; an unsupported final answer with no assessable calculation or interpretation
Part b (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: uses a conversion factor of 3; calculates 144 beats per minute; states that the rate is 1.6 beats per minute above the upper target limit. Accept 'about 2 beats per minute above' when whole-number target limits are used consistently. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: a response that omits the required evidence for convert a pulse count to a rate and compare limits; an unsupported final answer with no assessable calculation or interpretation
Part c (4 marks)
Award one mark for each observable checkpoint, to a maximum of 4: converts the two-minute count to 117 beats per minute; identifies two minutes as the first target-range reading; calculates the average rate of decrease as 11 beats per minute per minute; states a valid physiological or measurement limitation. Accept an equivalent limitation concerning the estimated maximum-heart-rate rule or pulse-count precision. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: a response that omits the required evidence for interpret a recovery-rate sequence; an unsupported final answer with no assessable calculation or interpretation
Question 4
(a) Route A has an 8-minute transfer and does not meet the rule. Route B has a 10-minute transfer and meets it.
Route A: 07:54 minus 07:46 is 8 minutes. Route B: 08:00 minus 07:50 is 10 minutes.
(b) Route A arrives at 08:22 with 18 minutes to spare. Route B arrives after the walk at 08:36 with 4 minutes to spare.
Route A buffer: 08:40 minus 08:22 is 18 minutes. Route B arrival: 08:28 plus 8 minutes is 08:36; its buffer is 4 minutes.
(c) Route B is the only route that meets the stated 10-minute connection rule and still arrives 4 minutes early, so it is the defensible recommendation. The recommendation assumes services run to timetable and the 8-minute walk is realistic.
Although Route A arrives earlier, its 8-minute transfer fails the reliability rule. Route B satisfies the rule and arrives before the session.
Detailed marking criteria
Part a (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: calculates Route A's transfer as 8 minutes; calculates Route B's transfer as 10 minutes; correctly compares both transfers with the 10-minute rule. Exact minute values are required. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: a response that omits the required evidence for calculate timetable transfer intervals; an unsupported final answer with no assessable calculation or interpretation
Part b (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: states Route A arrival as 08:22 with an 18-minute buffer; adds the 8-minute walk to obtain Route B arrival at 08:36; calculates Route B's buffer as 4 minutes. Exact clock times and minute intervals are required; accept equivalent 12-hour notation. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: a response that omits the required evidence for combine timetable and walking times; an unsupported final answer with no assessable calculation or interpretation
Part c (4 marks)
Award one mark for each observable checkpoint, to a maximum of 4: identifies that Route A arrives earlier; identifies that Route A fails the connection rule; recommends Route B because it meets the rule and arrives before 08:40; states one relevant timetable, walking-time or service-reliability assumption. Accept a Route A recommendation only if the candidate explicitly rejects or changes the supplied 10-minute reliability rule; otherwise Route B is required. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: choosing only the earliest arrival without applying the connection rule
Question 5
(a) The overtime rate is $47.25 per hour and gross pay is $1433.25.
The overtime rate is 31.50 × 1.5=47.25. Ordinary pay is 38 × 31.50=$1197.00, overtime pay is 5 × 47.25=$236.25, and gross pay is $1433.25.
(b) Taxable income is $1348.25, so the supplied PAYG withholding is $310.
Subtract the allowable deduction: 1433.25-85=1348.25. This lies in the supplied $1300-$1399.99 table row.
(c) Net pay is $1105.25. 22% of gross pay is $315.32, which is $5.32 more than the supplied table withholding.
Net pay is 1433.25-310-18=$1105.25. The estimate is 0.22(1433.25)=$315.315, or $315.32. The difference is $5.32.
Detailed marking criteria
Part a (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: calculates the overtime rate as $47.25; calculates ordinary and overtime earnings; adds the earnings to obtain gross pay of $1433.25. Accept money values to the nearest cent. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: a response that omits the required evidence for calculate ordinary and overtime earnings; an unsupported final answer with no assessable calculation or interpretation
Part b (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: subtracts $85 from gross pay; obtains taxable income of $1348.25; selects $310 from the correct PAYG row. Exact money values are required from the supplied table. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: using gross pay rather than supplied taxable income to select the table row
Part c (4 marks)
Award one mark for each observable checkpoint, to a maximum of 4: subtracts PAYG and the union fee to obtain $1105.25; calculates 22% of gross pay as $315.32; calculates the difference as $5.32; states that the supplied table amount is lower than the percentage estimate. Accept money values within one cent. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: subtracting the allowable deduction again when calculating net pay
Question 6
(a) Annual depreciation is $2700, and V_n=18,500-2700n for 0le nle5.
The depreciable amount is 18,500-5000=13,500. Divide by 5 to obtain $2700 per year.
(b) V_3=$10,400, and V_5=$5000.
V_3=18,500-2700(3)=10,400. Also V_5=18,500-2700(5)=5000.
(c) The first whole year is year 4, when V_4=$7700. Straight-line depreciation is required because the task specifies a constant annual dollar decrease to the residual value.
Solve 18,500-2700n<8000, giving n>3.888ldots. The first whole year is 4, and V_4=7700.
Detailed marking criteria
Part a (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: calculates the depreciable amount as $13,500; divides by 5 to obtain $2700 per year; writes V_n=18,500-2700n with an appropriate domain. Exact values are required; accept an equivalent recurrence V_(n+1)=V_n-2700, V_0=18,500. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Acceptable alternatives: the equivalent recurrence relation with initial value and yearly decrease
Do not credit by itself: a response that omits the required evidence for calculate and represent straight-line depreciation; an unsupported final answer with no assessable calculation or interpretation
Part b (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: substitutes n=3 to obtain $10,400; substitutes n=5 to obtain $5000; states that the second result verifies the residual-value condition. Exact dollar values are required. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: a response that omits the required evidence for substitute into a straight-line depreciation rule; an unsupported final answer with no assessable calculation or interpretation
Part c (4 marks)
Award one mark for each observable checkpoint, to a maximum of 4: forms or tests the inequality 18,500-2700n<8000; identifies the first whole year as 4; verifies V_4=$7700; explains that straight-line uses a constant dollar decrease rather than a constant percentage. Year 4 and $7700 are exact; accept trial-and-check using year 3 and year 4. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Acceptable alternatives: a year-by-year table that correctly identifies year 4
Do not credit by itself: a response that omits the required evidence for solve a depreciation threshold and distinguish depreciation models; an unsupported final answer with no assessable calculation or interpretation
Question 7
(a) Day total 60; night total 40; on-time total 78; late total 22; grand total 100.
The row totals are 48+12=60 and 30+10=40. The column totals are 48+30=78 and 12+10=22.
(b) Day shift: 20%. Night shift: 25%.
Day: 12 / 60 × 100=20%. Night: 10 / 40 × 100=25%.
(c) The claim is false: 25% is 1.25 times, not twice, the day-shift rate of 20%. A side-by-side column graph of the two conditional percentages is suitable.
The rate ratio is 25 / 20=1.25. The percentage-point difference is 5.
Detailed marking criteria
Part a (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: calculates both shift totals as 60 and 40; calculates both outcome totals as 78 and 22; checks the grand total as 100. Exact counts are required. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: a response that omits the required evidence for calculate marginal totals in a two-way table; an unsupported final answer with no assessable calculation or interpretation
Part b (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: uses 12 / 60 for the day shift; uses 10 / 40 for the night shift; states the conditional percentages as 20% and 25%. Exact percentages are expected; accept equivalent decimals 0.20 and 0.25 when labelled. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: a response that omits the required evidence for calculate conditional percentages from a two-way table; an unsupported final answer with no assessable calculation or interpretation
Part c (4 marks)
Award one mark for each observable checkpoint, to a maximum of 4: compares 25% with 20%; calculates a rate ratio of 1.25 or a 5-percentage-point difference; rejects the claim that the rate is twice as high; selects and justifies a suitable comparative display. Accept 1.25 times or a 5-percentage-point comparison; the display must compare conditional rates rather than raw counts. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Acceptable alternatives: a correctly labelled percentage bar chart or dot plot
Do not credit by itself: a response that omits the required evidence for evaluate a conditional-rate claim and choose a graph; an unsupported final answer with no assessable calculation or interpretation
Question 8
(a) Arc length =3piapprox9.42 m; sector area =6.75piapprox21.21 m^2.
Arc length =((120) / (360))(2π)(4.5)=3π. Area =((120) / (360))π(4.5)²=6.75π.
(b) The remainder area is 13.5piapprox42.41 m^2.
Full circle area is 20.25π. Subtracting 6.75π leaves 13.5piapprox42.41 m^2.
(c) Waste-adjusted area is about 22.90 m^2. This requires 22.9022ldots / 5=4.5804ldots kits, so 5 whole kits cost $700.
6.75π(1.08)=22.9022ldots m^2. Divide by 5 m² per kit to obtain 4.5804ldots, then round up to 5 purchasable kits. Cost =5(140)=$700.
Detailed marking criteria
Part a (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: selects the 120 / 360 sector fraction; calculates arc length 3piapprox9.42 m; calculates area 6.75piapprox21.21 m^2. Accept arc length within 0.01 m and area within 0.02 square metres. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: a response that omits the required evidence for calculate sector arc length and area; an unsupported final answer with no assessable calculation or interpretation
Part b (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: calculates full-circle area 20.25π m²; subtracts the coated sector area; states remainder 13.5piapprox42.41 m^2. Accept a remainder within 0.02 square metres. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: a response that omits the required evidence for calculate a complementary sector area; an unsupported final answer with no assessable calculation or interpretation
Part c (4 marks)
Award one mark for each observable checkpoint, to a maximum of 4: applies the 1.08 waste factor to obtain about 22.90 m²; divides by 5 m² per kit; rounds 4.5804ldots up to 5 whole kits; calculates total cost $700. Accept 5 kits and $700 from consistent use of the unrounded sector area. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: using ordinary money rounding on a theoretical per-square-metre cost; rounding the kit count down
Question 9
(a) Plan: 8 cm by 6 cm. Front elevation: 8 cm by 3.2 cm.
At 1:100, 1 m actual is 1 cm on the drawing.
(b) Door: 1.8 cm by 2.1 cm. The elevation should show the scale, overall dimensions, door dimensions and clear front-elevation labelling.
The same 1:100 conversion gives 1.8 cm and 2.1 cm.
(c) External wall area excluding the door is 85.82 m^2. The required cladding area is 94.402 m², or approximately 94.4 m^2. No purchase increment is specified, so no additional purchase-unit rounding is required.
Four-wall area is 2(8+6)(3.2)=89.6 m^2. Door area is 1.8(2.1)=3.78 m^2. Net area is 85.82 m², and 85.82(1.10)=94.402 m^2.
Detailed marking criteria
Part a (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: converts the 8 m length to 8 cm; converts the 6 m width to 6 cm; converts the 3.2 m height to 3.2 cm. Exact scale dimensions are required. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: a response that omits the required evidence for convert actual dimensions for a scale drawing; an unsupported final answer with no assessable calculation or interpretation
Part b (3 marks)
Award one mark for each observable checkpoint, to a maximum of 3: converts the door width to 1.8 cm; converts the door height to 2.1 cm; identifies required scale, dimension and elevation labels. Exact scaled dimensions are required; accept standard equivalent building-plan conventions. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Acceptable alternatives: a correctly dimensioned sketch using an equivalent conventional door placement
Do not credit by itself: a response that omits the required evidence for apply scale and building-drawing conventions; an unsupported final answer with no assessable calculation or interpretation
Part c (4 marks)
Award one mark for each observable checkpoint, to a maximum of 4: calculates four-wall area as 89.6 m²; subtracts door area 3.78 m² to obtain 85.82 m²; applies the 10% allowance to obtain 94.402 m²; reports approximately 94.4 m² with units without inventing a purchase increment. Accept the exact requirement 94.402 square metres or 94.4 square metres to one decimal place. Apply consequential marking to a correct later method that uses an earlier incorrect value, unless the error makes the later work materially easier.
Do not credit by itself: a response that omits the required evidence for calculate wall area from a building plan and apply waste; an unsupported final answer with no assessable calculation or interpretation
Diagnostic Checklist
| Topic | Questions | Marks | Marks Lost | Action |
|---|---|---|---|---|
| Essential Mathematics - Personal Level 2 (MEP215123) | Module 1: Application of percentages, rates and ratio, and budgeting | Criterion 6 | convert weekly income to a monthly spreadsheet input | Q1(a) | 3 | ___ | Q1(a): Practise converting weekly income to a monthly amount before entering it into a budget. |
| Essential Mathematics - Personal Level 2 (MEP215123) | Module 1: Application of percentages, rates and ratio, and budgeting | Criterion 6 | total car costs and calculate the monthly surplus | Q1(b) | 3 | ___ | Q1(b): Rebuild the car-cost and total-expense spreadsheet rows, then check income minus expenses. |
| Essential Mathematics - Personal Level 2 (MEP215123) | Module 1: Application of percentages, rates and ratio, and budgeting | Criterion 6 | compare budget options and justify a practical recommendation | Q1(c) | 4 | ___ | Q1(c): Rework both budget columns, compare the surpluses, then separate the financial conclusion from the practical consideration. |
| Essential Mathematics - Personal Level 2 (MEP215123) | Module 2: Probability and statistics | Criterion 7 | describe bivariate association by direction, form and strength | Q2(a) | 3 | ___ | Q2(a): Use all three association descriptors: direction, form and strength. |
| Essential Mathematics - Personal Level 2 (MEP215123) | Module 2: Probability and statistics | Criterion 7 | calculate and interpret a fitted line from two data points | Q2(b) | 3 | ___ | Q2(b): Recalculate the endpoint changes, preserve the negative sign, and substitute one point for the intercept. |
| Essential Mathematics - Personal Level 2 (MEP215123) | Module 2: Probability and statistics | Criterion 7 | interpolate from a fitted line and distinguish correlation from causation | Q2(c) | 4 | ___ | Q2(c): Rework the substitution, identify interpolation versus extrapolation, then explain the causation limitation. |
| Essential Mathematics - Personal Level 2 (MEP215123) | Module 1: Application of percentages, rates and ratio, and budgeting | Criterion 6 | calculate percentage limits for a target rate | Q3(a) | 3 | ___ | Q3(a): Apply both percentages to the estimated maximum, not to the measured pulse. |
| Essential Mathematics - Personal Level 2 (MEP215123) | Module 1: Application of percentages, rates and ratio, and budgeting | Criterion 6 | convert a pulse count to a rate and compare limits | Q3(b) | 3 | ___ | Q3(b): Convert the measured count to a one-minute rate before comparing it with the target limits. |
| Essential Mathematics - Personal Level 2 (MEP215123) | Module 1: Application of percentages, rates and ratio, and budgeting | Criterion 6 | interpret a recovery-rate sequence | Q3(c) | 4 | ___ | Q3(c): Use the six-minute elapsed time to calculate the average rate of decrease, not only the total reduction in pulse rate. |
| Essential Mathematics - Personal Level 2 (MEP215123) | Module 3: Measurement of energy and mass, and time and motion | Criterion 8 | calculate timetable transfer intervals | Q4(a) | 3 | ___ | Q4(a): Write both arrival and departure times on a timeline before comparing the transfer interval. |
| Essential Mathematics - Personal Level 2 (MEP215123) | Module 3: Measurement of energy and mass, and time and motion | Criterion 8 | combine timetable and walking times | Q4(b) | 3 | ___ | Q4(b): Add every stage, including the walk, then subtract each arrival time from 08:40. |
| Essential Mathematics - Personal Level 2 (MEP215123) | Module 3: Measurement of energy and mass, and time and motion | Criterion 8 | evaluate route feasibility against two constraints | Q4(c) | 4 | ___ | Q4(c): Make a two-constraint table for arrival and transfer reliability, then state the assumption behind the recommendation. |
| Essential Mathematics - Workplace Level 2 (MEW215123) | Module 1: Finance and money management | Criterion 6 | calculate ordinary and overtime earnings | Q5(a) | 3 | ___ | Q5(a): Separate the ordinary and overtime rows before totaling gross pay. |
| Essential Mathematics - Workplace Level 2 (MEW215123) | Module 1: Finance and money management | Criterion 6 | use a supplied PAYG table after an allowable deduction | Q5(b) | 3 | ___ | Q5(b): Calculate taxable income before selecting the matching PAYG interval. |
| Essential Mathematics - Workplace Level 2 (MEW215123) | Module 1: Finance and money management | Criterion 6 | reconcile net pay and compare withholding methods | Q5(c) | 4 | ___ | Q5(c): Reconcile gross pay to net pay line by line, then compare the two withholding amounts rather than their percentages. |
| Essential Mathematics - Workplace Level 2 (MEW215123) | Module 1: Finance and money management | Criterion 6 | calculate and represent straight-line depreciation | Q6(a) | 3 | ___ | Q6(a): Subtract residual value before dividing by asset life, then show the constant decrease in the rule. |
| Essential Mathematics - Workplace Level 2 (MEW215123) | Module 1: Finance and money management | Criterion 6 | substitute into a straight-line depreciation rule | Q6(b) | 3 | ___ | Q6(b): Substitute each year separately and compare the year-5 result with the supplied residual value. |
| Essential Mathematics - Workplace Level 2 (MEW215123) | Module 1: Finance and money management | Criterion 6 | solve a depreciation threshold and distinguish depreciation models | Q6(c) | 4 | ___ | Q6(c): Check consecutive whole years around the threshold, then compare constant-dollar and constant-percentage models. |
| Essential Mathematics - Workplace Level 2 (MEW215123) | Module 2: Interpreting graphs, representing and comparing data | Criterion 7 | calculate marginal totals in a two-way table | Q7(a) | 3 | ___ | Q7(a): Add across rows and down columns, then confirm both directions give the same grand total. |
| Essential Mathematics - Workplace Level 2 (MEW215123) | Module 2: Interpreting graphs, representing and comparing data | Criterion 7 | calculate conditional percentages from a two-way table | Q7(b) | 3 | ___ | Q7(b): Use each shift total as its own denominator. |
| Essential Mathematics - Workplace Level 2 (MEW215123) | Module 2: Interpreting graphs, representing and comparing data | Criterion 7 | evaluate a conditional-rate claim and choose a graph | Q7(c) | 4 | ___ | Q7(c): Compare like-for-like shift percentages, then choose a display that preserves that comparison. |
| Essential Mathematics - Workplace Level 2 (MEW215123) | Module 3: Measurement, scales, plans and models | Criterion 8 | calculate sector arc length and area | Q8(a) | 3 | ___ | Q8(a): Apply the same sector fraction to the circumference and circle area. |
| Essential Mathematics - Workplace Level 2 (MEW215123) | Module 3: Measurement, scales, plans and models | Criterion 8 | calculate a complementary sector area | Q8(b) | 3 | ___ | Q8(b): Use the uncoated 240-degree fraction or subtract the coated sector from the whole circle. |
| Essential Mathematics - Workplace Level 2 (MEW215123) | Module 3: Measurement, scales, plans and models | Criterion 8 | apply waste and whole-kit procurement rounding | Q8(c) | 4 | ___ | Q8(c): Round the kit count only after applying waste; kits are the defined purchasable unit. |
| Essential Mathematics - Workplace Level 2 (MEW215123) | Module 3: Measurement, scales, plans and models | Criterion 8 | convert actual dimensions for a scale drawing | Q9(a) | 3 | ___ | Q9(a): Convert metres to centimetres, then divide by 100; verify that this simplifies to 1 m actual per 1 cm drawing. |
| Essential Mathematics - Workplace Level 2 (MEW215123) | Module 3: Measurement, scales, plans and models | Criterion 8 | apply scale and building-drawing conventions | Q9(b) | 3 | ___ | Q9(b): Apply the same scale to the opening, then audit the drawing for scale, view and dimension labels. |
| Essential Mathematics - Workplace Level 2 (MEW215123) | Module 3: Measurement, scales, plans and models | Criterion 8 | calculate wall area from a building plan and apply waste | Q9(c) | 4 | ___ | Q9(c): Use actual dimensions for material area, subtract openings, then apply waste. Do not apply purchase-unit rounding because no purchase increment is supplied. |