Skill Align VCE General Mathematics Units 3&4 - Free Online Pack 0
Multiple-Choice Question Book | 40 questions | 40 marks
- Paper
- Examination 1 Showcase
- Reading
- 15 minutes
- Writing
- 1 hour 30 minutes
- Assessment
- 40 marks
Materials supplied: one Multiple-Choice Answer Sheet and one General Mathematics formula sheet. Materials permitted: one approved CAS calculator or CAS software, one scientific calculator, one bound reference that may be annotated, and basic stationery. Record every answer on the separate Multiple-Choice Answer Sheet. Pack 0 remains free online; no public answer-sheet, formula-sheet or PDF download is supplied.
Multiple-Choice Questions
Answer all questions. Choose the best answer for each question and record it on the separate Multiple-Choice Answer Sheet. Each question is worth 1 mark.
Question 1
1 mark- 3 minutes
- 3.5 minutes
- 4 minutes
- 4.5 minutes
Question 2
1 mark- 17
- 18
- 19
- 21
Question 3
1 mark- 8
- 16
- 36
- 72
Question 4
1 mark- -12
- 0
- 6
- 12
Question 5
1 mark- 68%
- 81.5%
- 95%
- 97.5%
Question 6
1 mark- 34%
- 40%
- 42.5%
- 46%
Question 7
1 mark- a pie chart
- parallel boxplots
- a segmented bar chart
- a single histogram
Question 8
1 mark- use = 9 + 0.8 temperature
- use = 22 - 0.8 temperature
- use = 0.8 + 9 temperature
- use = 9 - 0.8 temperature
Question 9
1 mark- a strong negative linear association
- a strong positive linear association
- no association
- a proven causal relationship
Question 10
1 mark- -4
- 4
- 47
- 98
Question 11
1 mark- 1.4
- 14.0
- 25.1
- 100
Question 12
1 mark- 0.1
- 1.1
- 1.5
- 12.6
Question 13
1 mark- 22
- 24
- 27
- 31
Question 14
1 mark- 3
- 5
- 7
- 12
Question 15
1 mark- 0.86
- 1.04
- 1.14
- 1.22
Question 16
1 mark- 340 units
- 378 units
- 420 units
- 468 units
Question 17
1 mark- 4200(1.0045)²⁴
- 4200(0.0045)²⁴
- 4200 + 24(1.0045)
- 4200(1.045)²⁴
Question 18
1 mark- 8%
- 12%
- 88%
- 112%
Question 19
1 mark- AUD 19,600
- AUD 20,230
- AUD 23,800
- AUD 25,270
Question 20
1 mark- AUD 2
- AUD 3
- AUD 6
- AUD 12
Question 21
1 mark- AUD 81,000
- AUD 180,000
- AUD 400,000
- AUD 810,000
Question 22
1 mark- the interest charged each period
- the repayment made each period
- the initial loan
- the number of repayments
Question 23
1 mark- 0.06%
- 0.6%
- 6%
- 7.2%
Question 24
1 mark- AUD 1,204
- AUD 1,300
- AUD 1,304
- AUD 1,400
Question 25
1 mark- -1
- 2
- 3
- 5
Question 26
1 mark- 2
- 5
- 8
- 13
Question 27
1 mark- 5
- 10
- 12
- 14
Question 28
1 mark- k = -1
- k = 1
- k = 3
- k = 9
Question 29
1 mark- 0.18
- 0.28
- 0.72
- 1.72
Question 30
1 mark- 72
- 156
- 240
- 13 104
Question 31
1 mark- 2 by 2
- 2 by 5
- 3 by 5
- 5 by 3
Question 32
1 mark- direct edges from A to D
- two-step walks from D to A
- three-step walks from A to D
- vertices adjacent to both A and D
Question 33
1 mark- every vertex has even degree and the network is connected
- exactly two vertices have odd degree
- every edge has the same weight
- there is a Hamiltonian path
Question 34
1 mark- 9 edges
- 10 edges
- 11 edges
- 12 edges
Question 35
1 mark- 9
- 10
- 11
- 13
Question 36
1 mark- 7
- 10
- 17
- 168
Question 37
1 mark- 5
- 8
- 13
- 40
Question 38
1 mark- 3
- 14
- 17
- 72
Question 39
1 mark- 18
- 20
- 22
- 24
Question 40
1 mark- 0 days
- 3 days
- 9 days
- 21 days
Worked Solutions And Marking Guide
Question 1
Answer: 4 minutes
There are 24 calls. The 12th and 13th observations both lie in the 4-minute category.
Question 2
Answer: 19
The fourth value in the ordered list is 19.
Question 3
Answer: 16
The interquartile range is 44 - 28 = 16.
Question 4
Answer: 0
The IQR is 12, so the lower fence is 18 - 1.5(12) = 0.
Question 5
Answer: 81.5%
The interval extends from one standard deviation below the mean to two standard deviations above it. Using the 68-95-99.7% rule, 34%+34%+13.5%=81.5%.
Question 6
Answer: 42.5%
34 divided by 80 is 0.425, or 42.5%.
Question 7
Answer: parallel boxplots
Parallel boxplots compare centre, spread and possible outliers for two numerical distributions.
Question 8
Answer: use = 9 + 0.8 temperature
The fitted line rises by about 0.8 units per degree and crosses the use axis near 9.
Question 9
Answer: a strong negative linear association
The magnitude is large and the sign is negative; correlation alone does not establish causation.
Question 10
Answer: -4
Residual = observed - predicted = 47 - 51 = -4.
Question 11
Answer: 25.1
The transformed prediction is 1.4, so y = 10^1.4, approximately 25.1.
Question 12
Answer: 1.5
For log(y) = log(a) + b log(x), the power is b = 1.5.
Question 13
Answer: 24
After ordering, 19, 22, 24, 27, 31, the middle value is 24.
Question 14
Answer: 7
Bookings fall from 52 to 45 between the fourth and fifth months, a decrease of 7.
Question 15
Answer: 1.14
Four quarterly indices sum to 4, so k = 4 - 2.86 = 1.14.
Question 16
Answer: 420 units
Deseasonalised sales = 378 / 0.90 = 420.
Question 17
Answer: 4200(1.0045)²⁴
Monthly compounding uses a multiplier of 1.0045 for 24 periods.
Question 18
Answer: 12%
A multiplier of 0.88 retains 88% of the value, so 12% is lost.
Question 19
Answer: AUD 20,230
The value is 28000(0.85)² = 20230.
Question 20
Answer: AUD 3
18000 / 6000 = AUD 3 per operating hour.
Question 21
Answer: AUD 400,000
Principal = annual payment / rate = 18000 / 0.045 = 400000.
Question 22
Answer: the repayment made each period
Interest is applied by the multiplier, then AUD 850 is subtracted as the repayment.
Question 23
Answer: 0.6%
Divide the nominal annual rate by 12: 7.2% / 12 = 0.6%.
Question 24
Answer: AUD 1,304
A(1) = 1.004(1000) + 300 = 1304.
Question 25
Answer: 2
Row 2, column 1 contains 2.
Question 26
Answer: 8
Row 1 of A dotted with column 2 of B gives 1(0) + 4(2) = 8.
Question 27
Answer: 10
The determinant is 4(3) - 1(2) = 10.
Question 28
Answer: k = 1
The determinant is 6k - 6, which is zero when k = 1.
Question 29
Answer: 0.28
Transition probabilities in a column sum to 1, so p = 1 - 0.72.
Question 30
Answer: 240
The total is 156 + 84 = 240.
Question 31
Answer: 3 by 5
The inner dimensions match; the outer dimensions are 3 and 5.
Question 32
Answer: three-step walks from A to D
Entries of the third power count walks of length three.
Question 33
Answer: every vertex has even degree and the network is connected
A connected network has an Euler circuit exactly when every vertex has even degree.
Question 34
Answer: 10 edges
Every tree with n vertices has n - 1 edges.
Question 35
Answer: 11
Selecting AC = 2, CD = 3 and AB = 6 connects all four vertices without a cycle for a total of 11.
Question 36
Answer: 17
Cut capacity is the sum 7 + 4 + 6 = 17.
Question 37
Answer: 13
The two routes can carry 5 + 8 = 13 units.
Question 38
Answer: 14
The shortest path is the route with minimum total length, 14.
Question 39
Answer: 22
Add the chosen assignment costs: 7 + 4 + 6 + 5 = 22.
Question 40
Answer: 3 days
Float = latest start - earliest start = 12 - 9 = 3 days.
Diagnostic Checklist
| Topic | Questions | Marks | Marks Lost | Action |
|---|---|---|---|---|
| Data Analysis | Q1 | 1 | ___ | Redo the calculation from its defining rule: There are 24 calls. The 12th and 13th observations both lie in the 4-minute category. |
| Data Analysis | Q2 | 1 | ___ | Redo the calculation from its defining rule: The fourth value in the ordered list is 19. |
| Data Analysis | Q3 | 1 | ___ | Order the data, calculate Q1, median and Q3 using the stated convention, then apply the 1.5 × IQR fences before comparing distributions. |
| Data Analysis | Q4 | 1 | ___ | Order the data, calculate Q1, median and Q3 using the stated convention, then apply the 1.5 × IQR fences before comparing distributions. |
| Data Analysis | Q5 | 1 | ___ | Standardise with z=((x-mu) / (sigma)), then interpret the sign and magnitude in standard-deviation units. |
| Data Analysis | Q6 | 1 | ___ | Redo the calculation from its defining rule: 34 divided by 80 is 0.425, or 42.5%. |
| Data Analysis | Q7 | 1 | ___ | Order the data, calculate Q1, median and Q3 using the stated convention, then apply the 1.5 × IQR fences before comparing distributions. |
| Data Analysis | Q8 | 1 | ___ | Redo the calculation from its defining rule: The fitted line rises by about 0.8 units per degree and crosses the use axis near 9. |
| Data Analysis | Q9 | 1 | ___ | Redo the calculation from its defining rule: The magnitude is large and the sign is negative; correlation alone does not establish causation. |
| Data Analysis | Q10 | 1 | ___ | Calculate residual = observed - predicted, then use its sign or the residual-plot pattern to assess the model. |
| Data Analysis | Q11 | 1 | ___ | Redo the calculation from its defining rule: The transformed prediction is 1.4, so y = 10^1.4, approximately 25.1. |
| Data Analysis | Q12 | 1 | ___ | Redo the calculation from its defining rule: For log(y) = log(a) + b log(x), the power is b = 1.5. |
| Data Analysis | Q13 | 1 | ___ | Redo the calculation from its defining rule: After ordering, 19, 22, 24, 27, 31, the middle value is 24. |
| Data Analysis | Q14 | 1 | ___ | Redo the calculation from its defining rule: Bookings fall from 52 to 45 between the fourth and fifth months, a decrease of 7. |
| Data Analysis | Q15 | 1 | ___ | Divide by the seasonal index to remove seasonality, multiply by it to restore seasonality, and align the forecast with the correct season. |
| Data Analysis | Q16 | 1 | ___ | Divide by the seasonal index to remove seasonality, multiply by it to restore seasonality, and align the forecast with the correct season. |
| Recursion and Financial Modelling | Q17 | 1 | ___ | Redo the calculation from its defining rule: Monthly compounding uses a multiplier of 1.0045 for 24 periods. |
| Recursion and Financial Modelling | Q18 | 1 | ___ | Choose the stated depreciation model, calculate adjacent values around any threshold, and retain the required scrap-value or domain constraint. |
| Recursion and Financial Modelling | Q19 | 1 | ___ | Choose the stated depreciation model, calculate adjacent values around any threshold, and retain the required scrap-value or domain constraint. |
| Recursion and Financial Modelling | Q20 | 1 | ___ | Choose the stated depreciation model, calculate adjacent values around any threshold, and retain the required scrap-value or domain constraint. |
| Recursion and Financial Modelling | Q21 | 1 | ___ | Use annual payment = principal × effective annual rate, allowing for any stated costs before distributing earnings. |
| Recursion and Financial Modelling | Q22 | 1 | ___ | Iterate the loan recurrence with interest applied before each repayment; reduce the final repayment when the interest-adjusted balance is below the regular payment. |
| Recursion and Financial Modelling | Q23 | 1 | ___ | Redo the calculation from its defining rule: Divide the nominal annual rate by 12: 7.2% / 12 = 0.6%. |
| Recursion and Financial Modelling | Q24 | 1 | ___ | Redo the calculation from its defining rule: A(1) = 1.004(1000) + 300 = 1304. |
| Matrices | Q25 | 1 | ___ | Redo the calculation from its defining rule: Row 2, column 1 contains 2. |
| Matrices | Q26 | 1 | ___ | Redo the calculation from its defining rule: Row 1 of A dotted with column 2 of B gives 1(0) + 4(2) = 8. |
| Matrices | Q27 | 1 | ___ | Redo the calculation from its defining rule: The determinant is 4(3) - 1(2) = 10. |
| Matrices | Q28 | 1 | ___ | Use the printed matrix dimensions and row-by-column products, then interpret the requested entry or vector in context. |
| Matrices | Q29 | 1 | ___ | Use the printed matrix dimensions and row-by-column products, then interpret the requested entry or vector in context. |
| Matrices | Q30 | 1 | ___ | Multiply the matrix by the state column vector using the printed row-and-column convention, then apply any stated culling, restocking or total constraint. |
| Matrices | Q31 | 1 | ___ | Redo the calculation from its defining rule: The inner dimensions match; the outer dimensions are 3 and 5. |
| Matrices | Q32 | 1 | ___ | Use the printed matrix dimensions and row-by-column products, then interpret the requested entry or vector in context. |
| Networks and Decision Mathematics | Q33 | 1 | ___ | Redo the calculation from its defining rule: A connected network has an Euler circuit exactly when every vertex has even degree. |
| Networks and Decision Mathematics | Q34 | 1 | ___ | Redo the calculation from its defining rule: Every tree with n vertices has n - 1 edges. |
| Networks and Decision Mathematics | Q35 | 1 | ___ | Apply Kruskal's or Prim's algorithm, reject any edge that closes a cycle, and confirm that all vertices are connected. |
| Networks and Decision Mathematics | Q36 | 1 | ___ | Construct a feasible source-to-sink flow, calculate a matching cut capacity, and use equality of the flow and cut to prove maximality. |
| Networks and Decision Mathematics | Q37 | 1 | ___ | Redo the calculation from its defining rule: The two routes can carry 5 + 8 = 13 units. |
| Networks and Decision Mathematics | Q38 | 1 | ___ | Use Dijkstra's algorithm: make the smallest temporary label permanent, update adjacent labels, and trace predecessor labels for the route. |
| Networks and Decision Mathematics | Q39 | 1 | ___ | Redo the calculation from its defining rule: Add the chosen assignment costs: 7 + 4 + 6 + 5 = 22. |
| Networks and Decision Mathematics | Q40 | 1 | ___ | Complete forward and backward scans, identify every zero-float path, and recalculate all affected paths after a duration change. |