Skill Align

Skill Align HSC Mathematics Standard 1 - Free Online Pack 0

Original Skill Align simulation paper aligned with the 2026 HSC Mathematics Standard 1 examination format.

Paper: HSC Mathematics Standard 1
Reading: 10 minutes
Writing: 2 hours
Assessment: 80 marks

NESA-approved calculators may be used. A reference sheet is provided separately with this paper as “Mathematics_Standard_1_and_2_Reference_Sheet.pdf”. Resource: https://www.nsw.gov.au/education-and-training/nesa/curriculum/mathematics/mathematics-standard-stage-6-2017

Section I

Attempt Questions 1-10. Allow about 15 minutes for this section. Select the best answer for each question.

Question 1

1 mark

Which variable is discrete numerical data?

A courier's preferred route
The mass of a parcel
The time taken for a delivery
The number of parcels delivered in one shift

Question 2

1 mark

A cyclist travels 6.3 km in 18 minutes. The average speed is

0.35 km / h
21 km / h
35 km / h
56.7 km / h

Question 3

1 mark

A map uses a scale of 1:50 000. A track measuring 7 cm on the map has actual length

0.35 km
3.5 km
35 km
350 km

Question 4

1 mark

Which vertex in the displayed walking-track network has degree 4?

Diagram Preview

Question 5

1 mark

A food stall earns revenue R = 15n and has cost C = 48 + 6n. Its profit from selling 12 meals is

AUD 36
AUD 60
AUD 108
AUD 180

Question 6

1 mark

A bag holds 5 red and 7 blue counters. Two red counters are drawn without replacement. The probability is

5 / 66
5 / 33
25 / 144
10 / 33

Question 7

1 mark

The number 0.000 582 written in standard form is

5.82 x 10⁻³
5.82 x 10⁻⁴
58.2 x 10⁻⁵
0.582 x 10⁻³

Question 8

1 mark

The chart shows 120 customer enquiries. Which category has relative frequency 0.25?

Graph Preview

Billing
Delivery
Returns
Product

Question 9

1 mark

AUD 12,000 is invested at 4.8% per annum compounded monthly for 3 years. The investment value is given by

12000(1.048)³
12000(1.004)³
12000(1.004)³⁶
12000(1.048)³⁶

Question 10

1 mark

A circular garden has diameter 9 m. Its circumference is

4.5π m
9π m
18π m
81π m

Section II

Attempt Questions 11-28. Allow about 1 hour and 45 minutes for this section. Show relevant mathematical reasoning and/or calculations.

Question 11

3 marks

A community centre reduces annual electricity use from 84 000 kWh to 69 300 kWh.

(a) 3 marks

Find the percentage reduction.

Question 12

2 marks

A ferry departs at 13:47 and arrives at 16:32.

(a) 2 marks

Find the journey time.

Question 13

3 marks

Five repair times, in minutes, are 18, 26, 14, 22 and 30.

(a) 1 mark

Find the range.

(b) 2 marks

Find the mean.

Question 14

5 marks

The weighted network shows travel times between emergency supply points.

Diagram Preview

(a) 3 marks

Find the shortest route from A to E and state its time.

(b) 2 marks

Explain why A-B-D-E is not the shortest route.

Question 15

8 marks

A container holds 7 green, 5 white and 3 orange tokens.

(a) 5 marks

Two tokens are drawn without replacement. Find the probability of drawing one green and one white in either order. Find the probability that at least one token is orange, and determine which event is more likely.

(b) 3 marks

For draws made with replacement, find the expected number of orange results in 80 draws and find the probability that a selected token is green given that it is not orange.

Question 16

3 marks

A pump transfers 720 L in 24 minutes.

(a) 1 mark

Find the transfer rate.

(b) 2 marks

Find the time to transfer 1.65 kL.

Question 17

2 marks

The chart shows the types of 96 bicycles serviced at a workshop.

Graph Preview

(a) 2 marks

Find the percentage that were e-bikes.

Question 18

3 marks

AUD 8,400 earns 3.8% per annum compounded annually.

(a) 3 marks

Find its value after 4 years, to the nearest cent.

Question 19

4 marks

A rectangular room measures 7.2 cm by 4.5 cm on a plan with scale 1:250.

(a) 2 marks

Find the actual dimensions in metres.

(b) 2 marks

Find the actual floor area.

Question 20

7 marks

The graph records battery charge during a 12-hour field test.

Graph Preview

(a) 4 marks

Calculate the average rate of change over each displayed interval and identify the interval with the greatest positive rate.

(b) 3 marks

Find the average rate of change over the complete test and explain why a single linear model with this gradient is unsuitable.

Question 21

3 marks

Researchers tag 180 fish. A later sample of 150 fish contains 36 tagged fish.

(a) 3 marks

Estimate the fish population.

Question 22

4 marks

The diagram shows a sector of radius 12 m and central angle 75 degrees.

Diagram Preview

(a) 2 marks

Find the exact area of the sector.

(b) 2 marks

Find the exact arc length.

Question 23

2 marks

A simplified schedule charges no tax on the first AUD 24,000 and 17% on income from AUD 24,001 to AUD 54,000.

(a) 2 marks

Find the tax payable on an income of AUD 54,000.

Question 24

5 marks

Equipment costs AUD 42,000 and has an expected value of AUD 10,500 after 7 years under straight-line depreciation.

(a) 2 marks

Find the annual depreciation.

(b) 2 marks

Find the value after 4 years.

(c) 1 mark

Find the total percentage depreciation over 7 years.

Question 25

4 marks

A community garden is a 14 m by 9 m rectangle with a 5 m by 3 m storage area removed.

Diagram Preview

(a) 2 marks

Find the planted area.

(b) 2 marks

Soil costs AUD 32 per square metre. Find the cost.

Question 26

4 marks

A delivery is delayed with probability 0.35. A parcel is late with probability 0.30 when there is a delay and 0.08 otherwise.

(a) 2 marks

Find the probability a parcel is late.

(b) 2 marks

Given a parcel is late, find the probability there was a delay.

Question 27

4 marks

The scatterplot compares machine operating hours and remaining battery charge.

Graph Preview

(a) 2 marks

Describe the association among the first six points.

(b) 2 marks

Identify the unusual point and explain why it may strongly affect a fitted line.

Question 28

4 marks

A loan of AUD 6,500 is charged 0.6% interest each month before a repayment of AUD 240.

(a) 2 marks

Write a recurrence for the balance L(n), with L(0) = 6500.

(b) 2 marks

Find the balance immediately after the second repayment, to the nearest cent.

Worked Solutions And Marking Guide

Section I Question 1

Answer: The number of parcels delivered in one shift

A parcel count is numerical and takes whole-number values.

Section I Question 2

Answer: 21 km / h

Eighteen minutes is 0.3 hours, so speed is 6.3 / 0.3 = 21 km / h.

Section I Question 3

Answer: 3.5 km

7(50000) = 350000 cm = 3.5 km.

Section I Question 4

Answer: C

Vertex C meets edges AC, BC, CD and CE.

Section I Question 5

Answer: AUD 60

Profit is 15(12) - [48 + 6(12)] = 180 - 120 = 60.

Section I Question 6

Answer: 5 / 33

The probability is (5 / 12)(4 / 11) = 5 / 33.

Section I Question 7

Answer: 5.82 x 10⁻⁴

Move the decimal point four places to the right to obtain 5.82.

Section I Question 8

Answer: Billing

Billing has 30 of 120 enquiries, so its relative frequency is 0.25.

Section I Question 9

Answer: 12000(1.004)³⁶

The monthly rate is 0.048 / 12 = 0.004 and there are 36 months.

Section I Question 10

Answer: 9π m

Circumference equals π times the diameter.

Section II Question 11

(a) 17.5%.

The reduction is 14 700 kWh, and 14700 / 84000 x 100 = 17.5%.

Mark allocation

Part a: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

Represents the quantities in part a with a valid successive percentage change relationship.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part a (1 mark)

Substitutes the values stated in part a consistently into that relationship.

Part a (1 mark)

Obtains the correct final result 17.5%.

Section II Question 12

(a) 2 hours 45 minutes.

From 13:47 to 15:47 is 2 hours, then to 16:32 is 45 minutes.

Mark allocation

Part a: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

From 13:47 to 15:47 is 2 hours.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part a (1 mark)

Obtains the correct final result 2 hours 45 minutes.

Section II Question 13

(a) 16 minutes.

30 - 14 = 16.

(b) 22 minutes.

The total is 110 and 110 / 5 = 22.

Mark allocation

Part a: accept the correct answer unless the prompt explicitly requires supporting reasoning.
Part b: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

Gives the correct result 16 minutes.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part b (1 mark)

The total is 110 and 110 / 5 = 22.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part b (1 mark)

Obtains the correct final result 22 minutes.

Section II Question 14

(a) A-C-D-E, 15 minutes.

The route totals 6 + 4 + 5 = 15 minutes.

(b) It takes 19 minutes.

The route total is 7 + 7 + 5 = 19, which is 4 minutes longer.

Mark allocation

Part a: award one mark for each distinct evidence statement in the criteria.
Part b: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

The route totals 6 + 4 + 5 = 15 minutes.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part a (1 mark)

Represents the quantities in part a with a valid minimum route relationship.

Part a (1 mark)

Obtains the correct final result A-C-D-E, 15 minutes.

Part b (1 mark)

The route total is 7 + 7 + 5 = 19, which is 4 minutes longer.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part b (1 mark)

States a conclusion supported by the preceding work: It takes 19 minutes.

Section II Question 15

(a) The probabilities are frac13 and ((13) / (35)), so drawing at least one orange token is more likely.

For one green and one white, add frac7(15)frac5(14)+frac5(15)frac7(14)=frac13. For at least one orange, use the complement 1-((12) / (15))((11) / (14))=1-((22) / (35))=((13) / (35)). Since ((13) / (35))>frac13, at least one orange is more likely.

(b) Expected orange results 16; conditional probability frac7(12).

The orange probability is 3 / 15, so the expected number is 80(3 / 15)=16. There are 12 non-orange tokens, of which 7 are green, so P(greenmidnot orange)=7 / 12.

Mark allocation

Part a: award one mark for each distinct evidence statement in the criteria.
Part b: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

For one green and one white, add frac7(15)frac5(14)+frac5(15)frac7(14)=frac13.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part a (1 mark)

For at least one orange, use the complement 1-((12) / (15))((11) / (14))=1-((22) / (35))=((13) / (35)).

Part a (1 mark)

Since ((13) / (35))>frac13, at least one orange is more likely.

Part a (1 mark)

Represents the quantities in part a with a valid multi-stage probability relationship.

Part a (1 mark)

Obtains the correct final result The probabilities are frac13 and ((13) / (35)), so drawing at least one orange token is more likely.

Part b (1 mark)

The orange probability is 3 / 15.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part b (1 mark)

The expected number is 80(3 / 15)=16.

Part b (1 mark)

Obtains the correct final result Expected orange results 16; conditional probability frac7(12).

Section II Question 16

(a) 30 L / min.

720 / 24 = 30.

(b) 55 minutes.

1.65 kL = 1650 L, and 1650 / 30 = 55.

Mark allocation

Part a: accept the correct answer unless the prompt explicitly requires supporting reasoning.
Part b: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

Gives the correct result 30 L / min.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part b (1 mark)

1.65 kL = 1650 L, and 1650 / 30 = 55.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part b (1 mark)

Obtains the correct final result 55 minutes.

Section II Question 17

(a) 31.25%.

30 / 96 x 100 = 31.25%.

Mark allocation

Part a: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

Represents the quantities in part a with a valid percentage from a chart relationship.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part a (1 mark)

Obtains the correct final result 31.25%.

Section II Question 18

(a) AUD 9,751.44.

Use 8400(1.038)⁴, which is approximately 9751.44.

Mark allocation

Part a: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

Use 8400(1.038)⁴, which is approximately 9751.44.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part a (1 mark)

Represents the quantities in part a with a valid compound growth relationship.

Part a (1 mark)

Obtains the correct final result AUD 9,751.44.

Section II Question 19

(a) 18 m by 11.25 m.

Multiply each plan length by 250 and convert centimetres to metres.

(b) 202.5 square metres.

18 x 11.25 = 202.5.

Mark allocation

Part a: award one mark for each distinct evidence statement in the criteria.
Part b: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

Multiply each plan length by 250 and convert centimetres to metres.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part a (1 mark)

Obtains the correct final result 18 m by 11.25 m.

Part b (1 mark)

18 x 11.25 = 202.5.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part b (1 mark)

Obtains the correct final result 202.5 square metres.

Section II Question 20

(a) The interval rates are 9, 5, -2 and 6 percentage points per hour; the greatest positive rate occurs from hour 0 to hour 2.

From 0 to 2 hours, (42-24) / 2=9. From 2 to 4 hours, (52-42) / 2=5. From 4 to 8 hours, (44-52) / 4=-2. From 8 to 12 hours, (68-44) / 4=6 percentage points per hour. The greatest is 9.

(b) The overall average rate is ((11) / (3)), or approximately 3.67, percentage points per hour; one linear model is unsuitable because the interval gradients change and one interval decreases.

The net change is 68-24=44 percentage points over 12 hours, so the overall average is 44 / 12=11 / 3. A single linear rule requires a constant gradient, but the displayed interval rates are 9,5,-2,6.

Mark allocation

Part a: award one mark for each distinct evidence statement in the criteria.
Part b: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

From 0 to 2 hours, (42-24) / 2=9.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part a (1 mark)

From 2 to 4 hours, (52-42) / 2=5.

Part a (1 mark)

From 4 to 8 hours, (44-52) / 4=-2.

Part a (1 mark)

Obtains the correct final result The interval rates are 9, 5, -2 and 6 percentage points per hour; the greatest positive rate occurs from hour 0 to hour 2.

Part b (1 mark)

The net change is 68-24=44 percentage points over 12 hours.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part b (1 mark)

The overall average is 44 / 12=11 / 3.

Part b (1 mark)

States a conclusion supported by the preceding work: The overall average rate is ((11) / (3)), or approximately 3.67, percentage points per hour; one linear model is unsuitable because the interval gradients change and one interval decreases.

Section II Question 21

(a) 750 fish.

Use 180 / N = 36 / 150, giving N = 180(150) / 36 = 750.

Mark allocation

Part a: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

Use 180 / N = 36 / 150, giving N = 180(150) / 36 = 750.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part a (1 mark)

Represents the quantities in part a with a valid capture-recapture relationship.

Part a (1 mark)

Obtains the correct final result 750 fish.

Section II Question 22

(a) 30π square metres.

(75 / 360)π(12)² = 30π.

(b) 5π metres.

(75 / 360)(2π)(12) = 5π.

Mark allocation

Part a: award one mark for each distinct evidence statement in the criteria.
Part b: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

(75 / 360)π(12)² = 30π.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part a (1 mark)

Obtains the correct final result 30π square metres.

Part b (1 mark)

(75 / 360)(2π)(12) = 5π.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part b (1 mark)

Obtains the correct final result 5π metres.

Section II Question 23

(a) AUD 5,100.

The taxable amount is 30000, so tax is 0.17(30000) = 5100.

Mark allocation

Part a: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

The taxable amount is 30000.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part a (1 mark)

Obtains the correct final result AUD 5,100.

Section II Question 24

(a) AUD 4,500.

The total loss is 31500 over 7 years.

(b) AUD 24,000.

42000 - 4(4500) = 24000.

(c) 75%.

31500 / 42000 = 0.75.

Mark allocation

Part a: award one mark for each distinct evidence statement in the criteria.
Part b: award one mark for each distinct evidence statement in the criteria.
Part c: accept the correct answer unless the prompt explicitly requires supporting reasoning.

Detailed marking criteria

Part a (1 mark)

The total loss is 31500 over 7 years.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part a (1 mark)

Obtains the correct final result AUD 4,500.

Part b (1 mark)

42000 - 4(4500) = 24000.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part b (1 mark)

Obtains the correct final result AUD 24,000.

Part c (1 mark)

Gives the correct result 75%.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Section II Question 25

(a) 111 square metres.

14(9) - 5(3) = 126 - 15 = 111.

(b) AUD 3,552.

111(32) = 3552.

Mark allocation

Part a: award one mark for each distinct evidence statement in the criteria.
Part b: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

14(9) - 5(3) = 126 - 15 = 111.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part a (1 mark)

Obtains the correct final result 111 square metres.

Part b (1 mark)

111(32) = 3552.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part b (1 mark)

Obtains the correct final result AUD 3,552.

Section II Question 26

(a) 0.157.

0.35(0.30) + 0.65(0.08) = 0.157.

(b) Approximately 0.669.

The joint probability is 0.105, so use 0.105 / 0.157.

Mark allocation

Part a: award one mark for each distinct evidence statement in the criteria.
Part b: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

Represents the quantities in part a with a valid conditional probability relationship.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part a (1 mark)

Obtains the correct final result 0.157.

Part b (1 mark)

The joint probability is 0.105.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part b (1 mark)

Obtains the correct final result Approximately 0.669.

Section II Question 27

(a) A strong negative association.

Charge generally falls as operating hours increase.

(b) The point near (10, 86); it has an extreme x-value and does not follow the trend.

Its horizontal separation gives it high leverage.

Mark allocation

Part a: award one mark for each distinct evidence statement in the criteria.
Part b: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

Charge generally falls as operating hours increase.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part a (1 mark)

States a conclusion supported by the preceding work: A strong negative association.

Part b (1 mark)

Its horizontal separation gives it high leverage.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part b (1 mark)

States a conclusion supported by the preceding work: The point near (10, 86); it has an extreme x-value and does not follow the trend.

Section II Question 28

(a) L(n+1) = 1.006L(n) - 240.

The existing balance is multiplied by 1.006 before the repayment is subtracted.

(b) AUD 6,096.79.

L(1) = 6500(1.006) - 240 = 6299. Then L(2) = 6299(1.006) - 240 = 6096.794, which rounds to AUD 6,096.79.

Mark allocation

Part a: award one mark for each distinct evidence statement in the criteria.
Part b: award one mark for each distinct evidence statement in the criteria.

Detailed marking criteria

Part a (1 mark)

The existing balance is multiplied by 1.006 before the repayment is subtracted.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part a (1 mark)

Obtains the correct final result L(n+1) = 1.006L(n) - 240.

Part b (1 mark)

L(1) = 6500(1.006) - 240 = 6299.

Acceptable alternatives: Accept an equivalent mathematically valid method that demonstrates the same assessable decision.

Part b (1 mark)

Obtains the correct final result AUD 6,096.79.

Diagnostic Checklist

Topic	Questions	Marks	Marks Lost	Action
Algebra and Modelling	Q5, Q7	2	___	Review the listed algebra and modelling items, their worked solutions and the evidence-specific marking criteria.
Financial Mathematics	Q9, Q18(a), Q23(a), Q24(a), Q24(b), Q24(c), Q28(a), Q28(b)	15	___	Review the listed financial mathematics items, their worked solutions and the evidence-specific marking criteria.
Measurement and Trigonometry	Q3, Q10, Q19(a), Q19(b), Q22(a), Q22(b), Q25(a), Q25(b)	14	___	Review the listed measurement and trigonometry items, their worked solutions and the evidence-specific marking criteria.
Networks	Q4, Q14(a), Q14(b)	6	___	Review the listed networks items, their worked solutions and the evidence-specific marking criteria.
Rates and Ratios	Q2, Q11(a), Q12(a), Q16(a), Q16(b), Q20(a), Q20(b)	16	___	Review the listed rates and ratios items, their worked solutions and the evidence-specific marking criteria.
Statistics and Probability	Q1, Q6, Q8, Q13(a), Q13(b), Q15(a), Q15(b), Q17(a), Q21(a), Q26(a), Q26(b), Q27(a), Q27(b)	27	___	Review the listed statistics and probability items, their worked solutions and the evidence-specific marking criteria.

HSC Mathematics Standard Free Online Pack 0 — HSC Mathematics Standard 1

Exam-pack paper structure

Read HSC Mathematics Standard 1 online

Section I

Question 1

Question 2

Question 3

Question 4

Question 5

Question 6

Question 7

Question 8

Question 9

Question 10

Section II

Question 11

Question 12

Question 13

Question 14

Question 15

Question 16

Question 17

Question 18

Question 19

Question 20

Question 21

Question 22

Question 23

Question 24

Question 25

Question 26

Question 27

Question 28

Worked Solutions And Marking Guide

Section I Question 1

Section I Question 2

Section I Question 3

Section I Question 4

Section I Question 5

Section I Question 6

Section I Question 7

Section I Question 8

Section I Question 9

Section I Question 10

Section II Question 11

Mark allocation

Detailed marking criteria

Section II Question 12

Mark allocation

Detailed marking criteria

Section II Question 13

Mark allocation

Detailed marking criteria

Section II Question 14

Mark allocation

Detailed marking criteria

Section II Question 15

Mark allocation

Detailed marking criteria

Section II Question 16

Mark allocation

Detailed marking criteria

Section II Question 17

Mark allocation

Detailed marking criteria

Section II Question 18

Mark allocation

Detailed marking criteria

Section II Question 19

Mark allocation

Detailed marking criteria

Section II Question 20

Mark allocation

Detailed marking criteria

Section II Question 21

Mark allocation

Detailed marking criteria

Section II Question 22

Mark allocation

Detailed marking criteria